CODEWITHSUNDEEP
php
Andris
Andris

Reputation: 1442

php base64_encode and glob can not get to work

Have this function that encodes content of images file to base64.

function data_uri($file_to_get_contents, $mime) {  
$contents = file_get_contents( '../images/'. $file_to_get_contents );
$base64 = base64_encode($contents);
return ('data:' . $mime . ';base64,' . $base64);
}

Actual location (url) of images file is this 

$val_img = '../images/2014-12-03/13-1-b5780ffc85f5f29d5ce43d1f4e38003f.gif';

I need to access echo image using such url (without .gif, .jpg etc.).

$val_img = '../images/2014-12-03/13-1-b5780ffc85f5f29d5ce43d1f4e38003f';

Decided to use glob. And use code below. 

$val_img = glob($val_img. '×.*');

Tried also 

$val_img = glob( '×'. $val_img. '*' );

With this see empty array 

echo '<pre>', print_r($val_img, true), '</pre> $val_img <br/>';

And with this 

echo '<img src='. data_uri($val_img , "../images"). ' alt="Image" >';

See error like Warning: file_get_contents(../images/Array) [<a href='function.file-get-contents'>function.file-get-contents</a>]: failed to open stream: No such file or directory

Error informs that in this $contents = file_get_contents( '../images/'. $file_to_get_contents ); line is error.

But seems something incorrect with this $val_img = glob($val_img. '×.*');

What would be correct code?

Here is my code that works

function data_uri($file_to_get_contents, $mime) {  
$contents = file_get_contents( '../images/'. $file_to_get_contents );
$base64 = base64_encode($contents); 
return ('data:' . $mime . ';base64,' . $base64);
}

$val_img = '../images/2014-12-03/13-1-b5780ffc85f5f29d5ce43d1f4e38003f';

$val_img = glob( $val_img. '*' );

echo '<img src='. data_uri($val_img[0] , "../images"). ' alt="Image" >';

Upvotes: 0

Views: 94

Answers (1)

elixenide
elixenide

Reputation: 44851

The problem is that you are passing an array to your function data_uri.

glob returns an array. That means that $val_img is an array, not a string. But you are treating it as a string when you pass it to data_uri as the parameter $file_to_get_contents. Specifically, you use it as a string in this line:

$contents = file_get_contents( '../images/'. $file_to_get_contents );

Easiest way to fix this: change your call to data_uri, like so:

echo '<img src='. data_uri($val_img[0] , "../images"). ' alt="Image" >';

Another option is to loop over the array, like this:

foreach($val_img as $one_img) {
    echo '<img src='. data_uri($one_img , "../images"). ' alt="Image" >';
}

Edit: You also have a logic error in your code. There's no need for the × character (whatever that is); your file names don't contain one. Just do $val_img = glob($val_img. '.*');

Side note: I have found that the best way to prevent these kinds of errors is to use a good IDE (I personally prefer PHPStorm) and add PHPDoc blocks to all your functions describing the parameter types. Then, if you try to pass an array when your function expects a string, you will get a warning from the IDE. Catching stuff like this at development time makes for much cleaner code and helps you avoid releasing errors into the wild.

Upvotes: 3

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