CODEWITHSUNDEEP
python
Deepika Soren
Deepika Soren

Reputation: 181

Printing result of re.search in python

I am a beginner in Python and struggling for a simple code. I have a string like :

ERROR_CODE=0,ERROR_MSG=null,SESSION_ID=2a50250f-4a2e-4bf9-b1a7-7a8030333de2|||33a3b23d-2143

I want to get the SESSION_ID=2a50250f-4a2e-4bf9-b1a7-7a8030333de2 from the string using re.search().

My Code:

line=ERROR_CODE=0,ERROR_MSG=null,SESSION_ID=2a50250f-4a2e-4bf9-b1a7-7a8030333de2|||33a3b23d-2143
sessionId=re.search(r'SESSION_ID=*|',line)
            if sessionId:
                print sessionId     
            else:
                print "Session id not found"

On executing this, i am getting the result as ,

<_sre.SRE_Match object at 0x0000000001EB8D98>

But i need the result as SESSION_ID=2a50250f-4a2e-4bf9-b1a7-7a8030333de2. Where i am going wrong?Thanks in advance

Upvotes: 1

Views: 8042

Answers (2)

Marcin
Marcin

Reputation: 238597

Your problem is 'SESSION_ID=|'. Character '|' should be escaped, and instead of * should be '.'.

sessionId=re.search(r'SESSION_ID=.*\|',line)

if sessionId:
    print(sessionId.group())     
else:
    print("Session id not found")

Result is:

SESSION_ID=2a50250f-4a2e-4bf9-b1a7-7a8030333de2|||

Probably there are better ways of doing your search for this, but I just applied the simplest changes to your regexp.

Better way would be e.g.

sessionId=re.search(r'(SESSION_ID=[\w-]+)\|',line)

if sessionId:
    print(sessionId.group(1))     
else:
    print("Session id not found")

This gives:

SESSION_ID=2a50250f-4a2e-4bf9-b1a7-7a8030333de2

Upvotes: 3

Hackaholic
Hackaholic

Reputation: 19753

search captures in group:
replace :

print sessionId

to:

print sessionId.group()

demo:

>>> a = "hello how are you"
>>> k= re.search('[a-z]+',a)
>>> k
<_sre.SRE_Match object at 0x7f9c456fe030>
>>> k.group()
'hello'

Upvotes: 0

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