CODEWITHSUNDEEP
phpregexpreg-match
user1960364
user1960364

Reputation: 2001

preg_match Regex Matching Full String

I have a simple regex, but it's matching more than I want...

Basically, I'm trying to match certain operators (eg. > < != =) followed by a string.

Regex:

/^(<=|>=|<>|!=|=|<|>)(.*)/

Example subject: 

>42

What I'm getting: 

array (size=3)
  0 => string '>42' (length=3)
  1 => string '>' (length=1)
  2 => string '42' (length=2)

What I'm trying to get: 

array (size=2)
  0 => string '>' (length=1)
  1 => string '42' (length=2)

What I don't understand is that my regex works perfectly on Regex101

Edit: To clarify, how can I get rid of the full string match?

Upvotes: 0

Views: 166

Answers (3)

mickmackusa
mickmackusa

Reputation: 47874

Not only will sscanf() return the exact desired flat array, it will cast that number (after the comparison symbols) as an integer. If a float is possible, use %f instead if %d.

Code: (Demo)

var_export(
    sscanf('>42', '%[<=>!]%d')
);

Upvotes: 0

Victory
Victory

Reputation: 5890

You are getting all 3 groups \0, \1, and '\2'. see the group matching at the bottom of the page

assuming your matches are in $matches you can run array_shift($matches) to remove the '\0' match if you wish.

Upvotes: 1

vks
vks

Reputation: 67968

Your answer is correct.Group(0) is the whole match.Group(1) if first group and group(2) is the second group.

Upvotes: 2

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