CODEWITHSUNDEEP
javascriptcoffeescript
Erik Nomitch
Erik Nomitch

Reputation: 1665

Coffeescript instance method encapsulation in an Object

Say I have a Coffeescript class:

class Foo
  MyMethodsBar: () => "bar"
  MyMethodsBaz: () => "baz"

Is there any way to encapsulate methods like this (not working):

class Foo
  MyMethods:
    bar: () => "bar"
    baz: () => "baz"

So I can call:

f = new Foo()
f.MyMethods.bar()

The problem is that this (or @) is not the instance when I do this like a regular method.

I'm trying to do this for cleaner mixins/concerns.

Thanks, Erik

Upvotes: 0

Views: 56

Answers (1)

Felix Kling
Felix Kling

Reputation: 816452

Nope, this is not possible, unless you create MyMethods inside the constructor and bind this to the methods. At which point you pretty much loose the benefits of using a class.

That's because when you call a method via f.MyMethods.bar(), this will refer to f.MyMethods. To prevent that, you could bind bar to specific object beforehand. However, at the moment you are defining bar, the instance of Foo to which this should refer to (f) does not exist yet, so you can't bind it outside of the constructor.

You could call the method with f.MyMethods.bar.call(f), but that's rather cumbersome.

Upvotes: 1

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