Reputation: 45
How can I get the interface name for the IP address in linux from C code ?
e.g. I'd like to get the interface name ( like etho , eth1 , l0 ) assigned for the IP address 192.168.0.1
Upvotes: 0
Views: 5748
Reputation: 592
You can use getifaddrs
. See man 3 getifaddrs for usage information. This will only work on a Unix-like systems.
Upvotes: 2
Reputation: 1657
netlink is a way to do this on Linux. I think it might even be a proper way to do it on Linux (even though it isn't portable).
The strategy is:
address_dq
) and record its interface (a number at this stage)The code below is not pretty, but I'm sure you could do a better job of it. I have been a especially sloppy by not checking for a multipart message (checking for the NLM_F_MULTI
flag and for a message type of NLMSG_DONE
is the way to do it). Instead I have just assumed the response to the first message is multipart -- it is on my machine -- and chewed up the NLMSG_DONE
message which follows.
Code...
#include <asm/types.h>
#include <linux/netlink.h>
#include <linux/rtnetlink.h>
#include <sys/socket.h>
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
int main(int argc, void ** argv) {
// This is the address we want the interface name for,
// expressed in dotted-quad format
char * address_dq = "127.0.0.1";
// Convert it to decimal format
unsigned int address;
inet_pton(AF_INET, address_dq, &address);
char buf[16384];
// Our first message will be a header followed by an address payload
struct {
struct nlmsghdr nlhdr;
struct ifaddrmsg addrmsg;
} msg;
// Our second message will be a header followed by a link payload
struct {
struct nlmsghdr nlhdr;
struct ifinfomsg infomsg;
} msg2;
struct nlmsghdr *retmsg;
// Set up the netlink socket
int sock = socket(AF_NETLINK, SOCK_RAW, NETLINK_ROUTE);
// Fill in the message
// NLM_F_REQUEST means we are asking the kernel for data
// NLM_F_ROOT means provide all the addresses
// RTM_GETADDR means we want address information
// AF_INET means limit the response to ipv4 addresses
memset(&msg, 0, sizeof(msg));
msg.nlhdr.nlmsg_len = NLMSG_LENGTH(sizeof(struct ifaddrmsg));
msg.nlhdr.nlmsg_flags = NLM_F_REQUEST | NLM_F_ROOT;
msg.nlhdr.nlmsg_type = RTM_GETADDR;
msg.addrmsg.ifa_family = AF_INET;
// As above, but RTM_GETLINK means we want link information
memset(&msg2, 0, sizeof(msg2));
msg2.nlhdr.nlmsg_len = NLMSG_LENGTH(sizeof(struct ifinfomsg));
msg2.nlhdr.nlmsg_flags = NLM_F_REQUEST | NLM_F_ROOT;
msg2.nlhdr.nlmsg_type = RTM_GETLINK;
msg2.infomsg.ifi_family = AF_UNSPEC;
// Send the first netlink message
send(sock, &msg, msg.nlhdr.nlmsg_len, 0);
int len;
// Get the netlink reply
len = recv(sock, buf, sizeof(buf), 0);
retmsg = (struct nlmsghdr *)buf;
// Loop through the reply messages (one for each address)
// Each message has a ifaddrmsg structure in it, which
// contains the prefix length as a member. The ifaddrmsg
// structure is followed by one or more rtattr structures,
// some of which (should) contain raw addresses.
while NLMSG_OK(retmsg, len) {
struct ifaddrmsg *retaddr;
retaddr = (struct ifaddrmsg *)NLMSG_DATA(retmsg);
int iface_idx = retaddr->ifa_index;
struct rtattr *retrta;
retrta = (struct rtattr *)IFA_RTA(retaddr);
int attlen;
attlen = IFA_PAYLOAD(retmsg);
char pradd[128];
// Loop through the routing information to look for the
// raw address.
while RTA_OK(retrta, attlen) {
if (retrta->rta_type == IFA_ADDRESS) {
// Found one -- is it the one we want?
unsigned int * tmp = RTA_DATA(retrta);
if (address == *tmp) {
// Yes!
inet_ntop(AF_INET, RTA_DATA(retrta), pradd, sizeof(pradd));
printf("Address %s ", pradd);
// Now we need to get the interface information
// First eat up the "DONE" message waiting for us
len = recv(sock, buf, sizeof(buf), 0);
// Send the second netlink message and get the reply
send(sock, &msg2, msg2.nlhdr.nlmsg_len, 0);
len = recv(sock, buf, sizeof(buf), 0);
retmsg = (struct nlmsghdr *)buf;
while NLMSG_OK(retmsg, len) {
struct ifinfomsg *retinfo;
retinfo = NLMSG_DATA(retmsg);
if (retinfo->ifi_index == iface_idx) {
retrta = IFLA_RTA(retinfo);
attlen = IFLA_PAYLOAD(retmsg);
char prname[128];
// Loop through the routing information
// to look for the interface name.
while RTA_OK(retrta, attlen) {
if (retrta->rta_type == IFLA_IFNAME) {
strcpy(prname, RTA_DATA(retrta));
printf("on %s\n", prname);
exit(EXIT_SUCCESS);
}
retrta = RTA_NEXT(retrta, attlen);
}
}
retmsg = NLMSG_NEXT(retmsg, len);
}
}
}
retrta = RTA_NEXT(retrta, attlen);
}
retmsg = NLMSG_NEXT(retmsg, len);
}
}
When run as above, returns Address 127.0.0.1 on lo
.
Using "192.168.1.x"
instead of "127.0.0.1"
it instead returns Address 192.168.1.x on eth0
.
Upvotes: 1
Reputation: 7802
Using /proc/net/arp you can match it. Here is a command line tool example.
usage: getdevicebyip 192.168.0.1
#include <stdio.h>
#include <fcntl.h>
int main(int argc, char **argv){
if (argc < 2) return 1;
FILE *fp = fopen("/proc/net/arp", "r");
char ip[99], hw[99], flags[99], mac[99], mask[99], dev[99], dummy[99];
fgets(dummy, 99, fp); //header line
while (fscanf(fp, "%s %s %s %s %s %s\n", ip, hw, flags, mac, mask, dev) != EOF)
if (!strcmp(argv[1],ip))
printf("%s\n",dev);
return 0;
}
Upvotes: 3