CODEWITHSUNDEEP
phpregex
Roel
Roel

Reputation: 764

Replacing characters after percent sign with regex

I would like to use RegEx to replace all text that comes after the percent sign in a string. Let's say I have the following string:

/path/to/webpage/%foo

I would like to use RegEx to replace %foo (this is variable and doesn't necessarily contain foo at all times) with $foo.

So far I have come up with the following expression, except this doesn't seem to work.

(%([a-z]+))\w

Any suggestions?

Thank you!

Upvotes: 1

Views: 384

Answers (1)

Hartmut Holzgraefe
Hartmut Holzgraefe

Reputation: 2765

Try an easier pattern, no ( subpattern matching needed here, just %.*$ for 'match all characters starting from '%' to the end of line':

<?php
$name = "/path/to/webpage/%foo";
$pattern = '/%.*$/';
$bar = 'bar';
$new_name =  preg_replace($pattern, $bar, $name);
echo "$new_name\n";

result:

/path/to/webpage/bar

Upvotes: 1

Related Questions