Reputation: 14864
How do I initialize an NSArray with size only so to use a for loop to fill it later? My for loop would be
for (int i = 0; i < [myArray count]; i++) {
myArray[i] = someData;
}
Upvotes: 11
Views: 16506
Reputation: 66242
You don't need to initialize it with a specific size - you can add objects later:
NSMutableArray *myArray = [NSMutableArray array];
for (int i = 0; i < 100; i++) {
[myArray addObject:someData];
}
There are slight performance gains if you know the size ahead of time:
NSMutableArray *myArray = [NSMutableArray arrayWithCapacity:100];
But this is optional.
Upvotes: 14
Reputation: 24481
NSNull
is the class used to represent an unset, invalid or non-existent object. Therefore you can pad the array to a specific size using instances of this class.
NSUInteger sizeOfArray = 10;
NSMutableArray *someArray = [NSMutableArray array];
for (NSUInteger i = 0; i < sizeOfArray; i++) {
[someArray addObject:[NSNull null]];
}
Further, you can't use the syntax someArray[i] = xyz;
if the value at position i
doesn't exist, as it will cause an out of bounds error.
Upvotes: 2