CODEWITHSUNDEEP
c++arrays
Vishnu Rajendran
Vishnu Rajendran

Reputation: 53

How to check for a value in an array

I have entered 4 numbers into an array using 

for (int i=0;i<4;i++)
{
    cin >> choice[i];
}

I need to check whether i have entered numbers 1,3,4,6(in any order) into the array

eg:-

if choice[0] == 1 && choice[1] == 3 && choice[2] == 4 && choice[3] == 6

else if ........ 1,3,6,4

else if..........1,6,3,4

else if.......1,6,4,3

else if......1,4,6,3

else if......1,4,3,6

....
....

else if.....6,4,3,1

this type of checking makes my code too big.

Please help me with an alternative way

Upvotes: 0

Views: 132

Answers (3)

Jarod42
Jarod42

Reputation: 217135

You may use something like:

std::vector<int> choice(4);
for (int i = 0; i < 4; ++i)
{
    std::cin >> choice[i];
}

std::sort(std::begin(choice), std::end(choice));
if (choice == std::vector<int>{1, 3, 4, 6}) { // 1, 3, 4, 6 should be sorted.
    // equal
}

Live example.

Upvotes: 0

Jonathan Mee
Jonathan Mee

Reputation: 38919

Use std::is_permutation:

int choice[4];

for (int i=0;i<4;i++)
{
    cin >> choice[i];
}

std::cout << std::is_permutation(std::begin(choice), std::end(choice), std::vector<int>{1, 3, 4, 6}.begin()) << std::endl;

Upvotes: 5

Danyal Sandeelo
Danyal Sandeelo

Reputation: 12391

bool count1=false;
bool count2=false;
bool count3=false;
bool count4=false;

for (int i=0;i<4;i++)
{
cin >> choice[i];
if(choice[i]==1) count1==true;
else if(choice[i]==3) count2=true;
else if(choice[i]==4) count3=true;
else if(choice[i]==6)  count4=true;
}

if(count1 && count2 && count3 && count4) cout<<endl<<"yes, it is!";

Upvotes: 3

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