CODEWITHSUNDEEP
makefile
Barry
Barry

Reputation: 302748

make target with same pattern twice

I have a bunch of libraries that I want to build as dependencies:

LIBS = libs/foo libs/bar

Each library has an object that I need to compile against, all in a predictable spot. They are:

libs/foo/lib/libfoo-O3.a
libs/bar/lib/libbar-O3.a

I would like to effectively transform my LIBS string into these rules:

build : libs/foo/lib/libfoo-O3.a libs/bar/lib/libbar-O3.a

libs/foo/lib/libfoo-O3.a:
    $(MAKE) -C libs/foo

libs/bar/lib/libbar-O3.a:
    $(MAKE) -C libs/bar

I know you can't use % twice, so unfortunately libs/%/lib/lib%-O3.a is a non-starter as a target. Is there another way to do this? Something with a define template?

Upvotes: 1

Views: 387

Answers (1)

MadScientist
MadScientist

Reputation: 100806

If you can change the LIBS variable to just contain the name, you can do it easily:

LIBS = foo bar

LIBPATHS := $(foreach L,$(LIBS),libs/$L/lib/lib$L-O3.a)

If you can't you can still do this, only slightly less readable:

LIBS = libs/foo libs/bar

LIBPATHS := $(foreach L,$(LIBS),$L/lib/lib$(notdir $L)-O3.a)

Then just add something like:

$(LIBPATHS):
        $(MAKE) -C $(firstword $(subst /lib/, ,$@))

Upvotes: 3

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