Reputation: 1153
I want to get specialization count for all the doctors and want to show it in the admin panel
Here are the models
class Doctor(models.Model):
name = models.CharField(max_length=1300)
specialization = models.ForeignKey(Specialization)
clinic = models.ForeignKey(Clinic)
class Specialization(models.Model):
name = models.CharField(max_length=30)
For instance, I want to show like:
Dermatologist: 10
Ophthalmologist: 15
I'm very new to Django and have no clue on how to go about it.
Upvotes: 0
Views: 105
Reputation: 45555
Don't use obj.doctor_set.count()
recipe. This method will be called for each Specialization record.
Use single SQL query with aggregation:
# admin.py
from django.contrib import admin
from django.db.models import Count
from app.models import Specialization
class SpecializationAdmin(admin.ModelAdmin):
list_display = ['name', 'doctor_count_display']
def get_queryset(self, request):
qs = super(SpecializationAdmin, self).get_queryset(request)
return qs.annotate(doctor_count=Count('doctor')).order_by('-doctor_count')
def doctor_count_display(self, obj):
return obj.doctor_count
doctor_count_display.short_description = 'Number of doctors'
doctor_count_display.admin_order_field = 'doctor_count'
admin.site.register(Specialization, SpecializationAdmin)
Upvotes: 1
Reputation: 37846
you can accomplish this in this way for example:
#admin.py
class SpecializationAdmin(admin.ModelAdmin):
list_display = ('get_count',)
def get_count(self, obj):
return u"{}: {}".format(obj.name, obj.doctor_set.count())
get_count.short_description = "Number of Doctors"
and register this like:
# also in admin.py
admin.site.register(Specialization, SpecializationAdmin)
dont forget to import Specialization
model into admin.py
Upvotes: 1
Reputation: 624
You need to understand about queries Django Queries
To show the number of dermatologist:
Doctor.objects.filter(specialization__name="Dermatologist").count()
To show the number of ophthalmologist
Doctor.objects.filter(specialization__name="Ophthalmologist").count()
Upvotes: 0