Reputation: 65
#include <stdio.h>
#include <conio.h>
struct node {
int data;
struct node* next;
};
int main() {
struct node* head = NULL;
struct node* second = NULL;
struct node* third = NULL;
head = (struct node*)malloc(sizeof(struct node));
second = (struct node*)malloc(sizeof(struct node));
third = (struct node*)malloc(sizeof(struct node));
head->data = 1;
head->next = second;
second->data = 2;
second->next = third;
third->data = 3;
third->next = NULL;
struct node* temp;
temp = head;
while (temp != NULL) { // for printing the linked list
printf("%d ",temp->data);
temp = temp->next;
}
struct node* new1;
struct node* temp1;
temp1 = head;
while (temp1 != NULL) { // for traversing to the end
temp1 = temp1->next;
}
new1 = (struct node*)malloc(sizeof(struct node));
new1->data = 5;
new1->next = NULL;
temp1->next = new1;
while (temp1 != NULL) { // again for printing the list
printf("%d ",temp1->data);
temp1 = temp1->next;
}
return 0;
}
I am trying to insert a node at the end of my linked list, but it is not working. I created the linked list successfully but I am not able to insert a node at the end. This is what my teacher taught me, but it is not working.
Upvotes: 3
Views: 166
Reputation: 17605
To my understanding, in the part that is commented
// for traversing to the end
the implementation iterates too far; the condition should be
while ( temp1->next != NULL )
to terminate as soon as the last node is reached, not if the terminating NULL
pointer is reached.
Upvotes: 2
Reputation: 9642
while(temp1 != NULL) // for traversing to the end
{
temp1 = temp1->next;
}
This will loop until temp1
is NULL
. You need to get the last node instead, i.e. when temp1->next
is NULL
, e.g.
while(temp1->next != NULL) // for traversing to the end
{
temp1 = temp1->next;
}
Upvotes: 2