Reputation: 14185
I try to convert interface{}
to struct person
...
package main
import (
"encoding/json"
"fmt"
)
func FromJson(jsonSrc string) interface{} {
var obj interface{}
json.Unmarshal([]byte(jsonSrc), &obj)
return obj
}
func main() {
type person struct {
Name string
Age int
}
json := `{"Name": "James", "Age": 22}`
actualInterface := FromJson(json)
fmt.Println("actualInterface")
fmt.Println(actualInterface)
var actual person
actual = actualInterface // error fires here -------------------------------
// -------------- type assertion always gives me 'not ok'
// actual, ok := actualInterface.(person)
// if ok {
// fmt.Println("actual")
// fmt.Println(actual)
// } else {
// fmt.Println("not ok")
// fmt.Println(actual)
// }
}
... But got error:
cannot use type interface {} as type person in assignment: need type assertion
To solve this error I tried to use type assertion actual, ok := actualInterface.(person)
but always got not ok
.
Upvotes: 3
Views: 9472
Reputation:
The usual way to handle this is to pass a pointer to the output value to your decoding helper function. This avoids type assertions in your application code.
package main
import (
"encoding/json"
"fmt"
)
func FromJson(jsonSrc string, v interface{}) error {
return json.Unmarshal([]byte(jsonSrc), v)
}
func main() {
type person struct {
Name string
Age int
}
json := `{"Name": "James", "Age": 22}`
var p person
err := FromJson(json, &p)
fmt.Println(err)
fmt.Println(p)
}
Upvotes: 6
Reputation: 23617
Your problem is that you're creating an empty interface to begin with, and telling json.Unmarshal
to unmarshal into it. While you've defined a person
type, json.Unmarshal
has no way of knowing that that's what you intend the type of the JSON to be. To fix this, move the definition of person
to the top level (that is, move it out of the body of main), and change
FromJson` to this:
func FromJson(jsonSrc string) interface{} {
var obj person{}
json.Unmarshal([]byte(jsonSrc), &obj)
return obj
}
Now, when you return obj
, the interface{}
that's returned has person
as its underlying type. You can run this code on the Go Playground.
By the way, your code is a bit un-idiomatic. I left the original Playground link unmodified except for my corrections so that it wouldn't be needlessly confusing. If you're curious, here's a version that's cleaned up to be more idiomatic (including comments on why I made the changes I did).
Upvotes: 5