CODEWITHSUNDEEP
javascriptbuild-processgulpjshint
Srle
Srle

Reputation: 10496

gulp-jshint specify files which should go through jshint() and ignore other files

I have situation where i'm building minified script through gulp, from scripts that are either vendor scripts or my scripts, something like:

var paths = {
    public      : './public/javascripts',
    api         : './public/API',
    vendor      : './public/vendor',
    destination : './dist'
};

gulp.task('scripts-out', function() {
    gulp.src([
        paths.public + '/a.js',
        paths.public + '/b.js',
        paths.public + '/c.js',
        paths.public + '/d.js',
        paths.api    + '/e.js',
        paths.public + '/f.js'
    ])
    .pipe(jshint())
    .pipe(jshint.reporter('default'))
    .pipe(concat('out.js'))
    .pipe(gulp.dest(paths.destination + '/javascripts'));
});

Only e.js is not vendor script and only that script should go through jshint(), from official documentation of the plugin i can't see solution for this.

I tried passing config object to jshint(), something like:

pipe(jshint({
    files: paths.api     + '/e.js'
}))

That was just speculation which don't work. Side question of this how to force jshint to write results to some file instead of console?

EDIT: FIND SOLUTION I find the way through the .jshintignore file, which should be in the root of the project, for example if you want to ignore all from the vendor folder you can just add one line to .jshintignore file: public/src/vendor/*

Upvotes: 4

Views: 1740

Answers (1)

Ben
Ben

Reputation: 10104

You could use gulp-filter to filter which files get passed to jshint:

var gulpFilter = require('gulp-filter');
var filter = gulpFilter([paths.public + '/e.js']);

gulp.task('scripts-out', function() {
    return gulp.src([
        paths.public + '/a.js',
        paths.public + '/b.js',
        paths.public + '/c.js',
        paths.public + '/d.js',
        paths.api    + '/e.js',
        paths.public + '/f.js'
    ])
    .pipe(filter)
    .pipe(jshint())
    .pipe(jshint.reporter('default'))
    .pipe(filter.restore())
    .pipe(concat('out.js'))
    .pipe(gulp.dest(paths.destination + '/javascripts'));
});

New version(3.0.1) has interface updates: 

 // you should pass {restore: true} for restore ability
 var filter = gulpFilter([paths.public + '/e.js'], {restore: true});
 ...
 // filter.restore is now object, not a method
 .pipe(filter.restore)

Upvotes: 3

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