CODEWITHSUNDEEP
javajson
John Smith
John Smith

Reputation: 6269

Problems decoding JSON with json-simple

I followed this tutorial on how to decode json with java: https://code.google.com/p/json-simple/wiki/DecodingExamples

In my project i get info_string:

   {"server_ip":"http://localhost:3000/","device_id":14}

that i would like to decode: I tried:

  System.out.println(info_string);
 => {"server_ip":"http://localhost:3000/","device_id":14}
  Object obj = JSONValue.parse(info_string);
  System.out.println(obj);
 => null
  JSONArray array=(JSONArray)obj;
 => null
  System.out.println(array);

As you can see the array and obj variable are null and contain no data! What do i wrong? Thanks

Upvotes: 0

Views: 146

Answers (1)

Alexis C.
Alexis C.

Reputation: 93872

There are certainly non-printable/invisible characters. I suggest you to use a regular expression to remove them, because if you String looks like 

String info_string = "   {\"server_ip\":\u0000\"http://localhost:3000/\",\"device_id\":14}";

trim() will do nothing.

So try with:

Object obj = JSONValue.parse(info_string.replaceAll("\\p{C}", ""));

and how can i get the single values? For example device_id from this obj?

In your case, parse will return a JSONObject, so you can cast the result, and then use the get method to get the value associated with the corresponding key:

JSONObject obj = (JSONObject) JSONValue.parse(info_string);
String serverIp = (String) obj.get("server_ip"); //http://localhost:3000/    
long deviceId = (Long) obj.get("device_id"); //14

Upvotes: 1

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