CODEWITHSUNDEEP
javaregex
fhaider
fhaider

Reputation: 165

Regex: How to include character of "if" condition

I'm making a date extractor using regex in java. Problem is that date is 20-05-2014 and my program is extracting 0-5-14. In short, how can I get the character on which I'm checking the second character of date? 

    int count = 0;
    String data = "HellowRoldsThisis20-05-2014. [email protected]@gmail.com";
    String regexOfDate = "((?<=[0])[1-9]{2})|((?<=[12])[0-9])|((?<=[3])[01])\\.\\-\\_((?<=[0])[1-9])|((?<=[1])[0-2])\\.\\-\\_((?<=[2])[0-9]{4})"; \\THE PROBLEM
    String[] extractedDate = new String[1000];
    Pattern patternDate = Pattern.compile(regexOfDate);
    Matcher matcherDate = patternDate.matcher(data);

    while(matcherDate.find()){           
        System.out.println("Date "+count+"Start: "+matcherDate.start());
        System.out.println("Date "+count+"End  : "+matcherDate.end());
        extractedDate[count] = data.substring(matcherDate.start(), matcherDate.end());
        System.out.println("Date Extracted: "+extractedDate[count]);
    }

Upvotes: 2

Views: 82

Answers (2)

Toto
Toto

Reputation: 91430

A single regex o match valid dates is awful.

I'd do:

String regexOfDate = "(?<!\\d)\\d{2}[-_.]\\d{2}[-_.]\\d{4}(?!\\d)";

to extract the potential date, then test if it is valid.

Upvotes: 0

Paul Vargas
Paul Vargas

Reputation: 42030

You can try the regular expression:

// (0[1-9]|[12][0-9]|[3][01])[._-](0[1-9]|1[0-2])[._-](2[0-9]{3})
"(0[1-9]|[12][0-9]|[3][01])[._-](0[1-9]|1[0-2])[._-](2[0-9]{3})"

Debuggex

Upvotes: 2

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