CODEWITHSUNDEEP
phphtmlmysqlarrays
vas_bar_code
vas_bar_code

Reputation: 213

Arrayed input value inserts empty record in mysql

I use 4 input boxes with same name.I will fill only one input box at a time and insert in DB using php.But doing following method inserts three empty records along with value-filled 4 th record.Need help!

Html

                <input type="text" name="abc[]" id="abc" value=""> 
                <input type="text" name="abc[]" id="abc"  value="">
                <input type="text" name="abc[]" id="abc"  value="">
                <input type="text" name="abc[]" id="abc" value="">

Php

$abc = $_POST['abc'];
        if (is_array($abc)) {
                foreach($abc as $c) {

$insert="INSERT INTO item(productid) VALUES ('$c')";
                    $insert2=mysql_query($insert);              }

}

Upvotes: 1

Views: 93

Answers (2)

david strachan
david strachan

Reputation: 7228

The following code produces 1 INSERT statement. If as you suggest you are only using 1 value from your input, and can enforce this you can omit $value = rtrim($value, ","); which removes the trailing ,.

I would also advise you to use either mysqli or PDO because mysql_functions are deprecated.

 $value = "";
if(isset($_POST['submit'])){
    if(isset($_POST['abc'])){
        foreach($_POST['abc'] as $c) {
        if(!empty($c)){
        $value .= "'".$c."',";}
        }
        $value = rtrim($value, ",");
    }
    $insert="INSERT INTO item(productid) VALUES ($value)";
    echo $insert;//Remove after testing
}

Upvotes: 1

Reza-S4
Reza-S4

Reputation: 1052

just check if the value is not empty then insert to database.

$abc = $_POST['abc'];
if (is_array($abc)) {
    foreach ($abc as $c) {
        if(!empty($c)){
            $insert = "INSERT INTO item(productid) VALUES ('$c')";
            $insert2 = mysql_query($insert);
        }
    }

}

Upvotes: 3

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