CODEWITHSUNDEEP
javaregexstringdate
RahSin
RahSin

Reputation: 287

Date parsing using regular expression

I am using regular expression to parse date formats from a string . It could be like

1/1/11
01/01/11
01/01/2011
01/1/2011
1/11/2011
1/11/11
11/1/11

Java code:

public static String getDateFromRemarks(String str) {
    String parsedDate = null;
    if (str != null) {
        String regex = ".*([0-3]?[0-9]/[0-3]?[0-9]/(?:[0-9]{2})?[0-9]{2}).*";

        Pattern pattern = Pattern.compile(regex);

        Matcher matcher = pattern.matcher(str);
        if (matcher.find()) {
            parsedDate = matcher.group(1);
        }
    }
    return parsedDate;
}

Input:

kjs22/12/2011 kjdflk

Output:

2/12/2011

Input:

kjs2/12/2011 kjdflk

Output:

2/12/2011

I should get date as

22/12/2011

Upvotes: 0

Views: 85

Answers (1)

fge
fge

Reputation: 121712

This is because of your initial .*. It swallows everything then backtracks.

And since the first digit is optional before your first /, the regex is satisfied with only one digit even if there are two.

Change your initial .* to [^\d]*.

Upvotes: 3

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