CODEWITHSUNDEEP
swiftasynchronousparse-platformoption-type
AppDever
AppDever

Reputation: 707

Swift ! does not remove Optional()

Before, I have successfully added a ! to force an unwrap to remove the "Optional()" from a variable. I am unable to do this in data returned from Parse.com

    query.findObjectsInBackgroundWithBlock {
        (objects: [AnyObject]!, error: NSError!) -> Void in
        if error == nil {

            for object in objects {
                println(object[myObject]!)
            }

        } else {
            println("Error: \(error) \(error.userInfo!)")
        }

    }

In the example above, the entire table from the Parse.com class is returned and printed to the console. However,

Optional(...)

is returned for each line even though I force an unwrap using ! at the end

What am I missing?

(Note: myObject is the name of the Column in the Parse Class database)

Upvotes: 12

Views: 12503

Answers (2)

walter
walter

Reputation: 21

You only have to put "!" at the end of your variable, in print area

self.addressLabel.text = "\(subThoroughfare) \(p.thoroughfare!) \n \(p.subLocality!) \n \(p.subAdministrativeArea!) \n)".

Upvotes: 2

AppDever
AppDever

Reputation: 707

MirekE was right. It was a nested Optional(Optional()).

to fix I:

println(object[myObject]!!)

Upvotes: 16

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