Reputation: 347
I need to concatenate values of XML based on this following:
Here is my XML:
<?xml version="1.0" encoding="utf-8"?>
<Root>
<Parent>
<Name>Father 1</Name>
<Child>
<Name>F1 - Child 1</Name>
<Age>2</Age>
</Child>
<Child>
<Name>F1- Child 2</Name>
<Age>4</Age>
</Child>
</Parent>
<Parent>
<Name>Father 2</Name>
<Child>
<Name>F2 - Child 1</Name>
<Age>2</Age>
</Child>
<Child>
<Name>F2 - Child 2</Name>
<Age>4</Age>
</Child>
</Parent>
</Root>
And here is my XSLT:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
<xsl:output method="xml" indent="yes"/>
<xsl:template match ="Root">
<xsl:apply-templates select ="Parent/Name" />
<xsl:apply-templates select ="Parent/Child" />
</xsl:template>
<xsl:template match ="Parent/Name">
<FatherName>
<xsl:value-of select ="."/>
</FatherName>
</xsl:template>
<xsl:template match ="Parent/Child">
<ChildNames>
<xsl:for-each select="Name">
<xsl:value-of select="." />
<xsl:if test="position()!=last()">
<xsl:text>, </xsl:text>
</xsl:if>
</xsl:for-each>
</ChildNames>
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Which results to this
<?xml version="1.0" encoding="utf-8"?>
<FatherName>Father 1</FatherName>
<FatherName>Father 2</FatherName>
<ChildNames>F1 - Child 1</ChildNames>
<ChildNames>F1- Child 2</ChildNames>
<ChildNames>F2 - Child 1</ChildNames>
<ChildNames>F2 - Child 2</ChildNames>
But the result I need is something like this:
<FatherName>Father 1</FatherName>
<ChildNames>F1 - Child 1, F1- Child 2</ChildNames>
<FatherName>Father 2</FatherName>
<ChildNames>F2 - Child 1, F2 - Child 2</ChildNames>
Can anyone help me to get the result I need?
Upvotes: 2
Views: 3446
Reputation: 640
came up with this
<xsl:template match="/">
<good>
<xsl:for-each select="Root/Parent">
<FatherName>
<xsl:value-of select="Name"/>
</FatherName>
<xsl:variable name="childCount" select="count(.//Child)"/>
<ChildNames>
<xsl:variable name="data">
<xsl:for-each select=".//Child">
<xsl:value-of select="Name"/>
<xsl:if test="not(position()=$childCount)">
<xsl:text>, </xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$data"/>
</ChildNames>
</xsl:for-each>
</good>
</xsl:template>
Upvotes: 0
Reputation: 70648
Essentially, what you need to do is move the line <xsl:apply-templates select ="Parent/Child" />
out of the current template, and into the template that matches Parent/Name
. Something like this:
<xsl:template match="Parent/Name">
<FatherName>
<xsl:value-of select ="."/>
</FatherName>
<ChildNames>
<xsl:apply-templates select ="../Child" />
</ChildNames>
</xsl:template>
The ..
here is to go back up to the Parent
node so you can then select the child nodes. Note, you also don't need the xsl:for-each
in the template matching child.
Actually, it might be easier to match on the Parent
node than the Parent/name
node.
Try this XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="Root">
<xsl:apply-templates select="Parent" />
</xsl:template>
<xsl:template match="Parent">
<FatherName>
<xsl:value-of select ="Name"/>
</FatherName>
<ChildNames>
<xsl:apply-templates select ="Child" />
</ChildNames>
</xsl:template>
<xsl:template match="Child">
<xsl:if test="position()!=1">
<xsl:text>, </xsl:text>
</xsl:if>
<xsl:value-of select="Name" />
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Upvotes: 3