Reputation: 409
I have two lists which I'd like to compare and if there is any match (even if partial) then carry out some action. I've set up this test code:
keywords = ['social media','social business','social networking','social marketing','online marketing','social selling',
'social customer experience management','social cxm','social cem','social crm','google analytics','seo','sem',
'digital marketing','social media manager','community manager']
metakeywords = ['top 10', 'social media blog', 'social media blog nomination']
if any(key in metakeywords for key in keywords):
print 'Ok'
As you can see, there is a partial match between the 1st item of keywords
and the 2nd and 3rd item of metakeywords
, so it should print Ok
. How can I do this?
Thanks!
Dani
Upvotes: 3
Views: 233
Reputation: 59103
If you want to find out if any item in keywords
is contained in any item in metakeywords
, you can do this:
if any(key in metakey for key in keywords for metakey in metakeywords):
print 'ok'
Upvotes: 7