CODEWITHSUNDEEP
javatimeduration
Eddinho
Eddinho

Reputation: 1369

how to convert minutes to days,hours,minutes

how to convert minutes into days hours and minutes in java ( we have a week here , 7 days )

 public String timeConvert(int time){
   String t = "";

   int h = 00;
   int m = 00;

  // h= (int) (time / 60);
  // m = (int) (time % 60);

  // if(h>=24) h=00;

   if((time>=0) && (time<=24*60)){
      h= (int) (time / 60);
      m = (int) (time % 60);
   }else if((time>24*60) && (time<=24*60*2)){
       h= (int) (time / (1440));
      m = (int) (time % (1440));
   }else if((time>24*60*2) && (time<=24*60*3)){
       h= (int) (time / (2880));
      m = (int) (time % (2880));
   }else if((time>24*60*3) && (time<=24*60*4)){
       h= (int) (time / (2880*2));
      m = (int) (time % (2880*2));
   }else if((time>24*60*4) && (time<=24*60*5)){
       h= (int) (time / (2880*3));
      m = (int) (time % (2880*3));
   }else if((time>24*60*5) && (time<=24*60*6)){
       h= (int) (time / (2880*4));
      m = (int) (time % (2880*4));
   }else if((time>24*60*6) && (time<=24*60*7)){
       h= (int) (time / (2880*5));
      m = (int) (time % (2880*5));
   }

   t =h+":"+m ;
   return t;
 }

I tried this but it dont work

thanks

Upvotes: 21

Views: 75028

Answers (15)

Fandango68
Fandango68

Reputation: 4838

For those looking for an SQL version of this logic:

where c.a_ARR is a Start Datetime, c.a_DEP is an End DateTime

       CASE WHEN DATEDIFF(minute, c.a_ARR, c.a_DEP)/60/24 = 0.0
            THEN ''
            ELSE FORMAT(DATEDIFF(minute, c.a_ARR, c.a_DEP)/60/24,'0') + 'd'
       END +
       CASE WHEN DATEDIFF(minute, c.a_ARR, c.a_DEP)/60%24 = 0.0 
            THEN ''
            ELSE FORMAT(DATEDIFF(minute, c.a_ARR, c.a_DEP)/60%24,'0') + 'h'
       END +
       CASE WHEN DATEDIFF(minute, c.a_ARR, c.a_DEP)%60 = 0.0
            THEN ''
            ELSE FORMAT(DATEDIFF(minute, c.a_ARR, c.a_DEP)%60,'0') + 'm'
       END AS [Duration]

Upvotes: 0

cre2
cre2

Reputation: 41

In case someone wants to use the accepted answer for JavaScript, time will be shown with decimals. In order to remove those decimals, you can use this code:

function timeConvert(time)
{ 
   return parseInt(time/24/60) + " days," + parseInt(time/60%24) + ' hours,' + parseInt(time%60) + " minutes";
}

Upvotes: 4

Asmaa Mohamed
Asmaa Mohamed

Reputation: 11

just make method return string and take( int minuts) String getTextOfTime(int minuts) {return result

String getTextOfTime(int minuts) {

int weeks = (-minuts / 10080).toInt();
int aboveWeeks = -minuts % 10080;
int days = (aboveWeeks / 1440).toInt();
int aboveDays = (aboveWeeks % 1440);
int hours = (aboveDays / 60).toInt();
int aboveHours = aboveDays % 60;
int minute = aboveHours;

String result = "";

if (weeks != 0) {
  result += weeks.toString();
  if (weeks == 1) {
    result += " week ";
  } else {
    result += " weeks ";
  }
}

if (days != 0) {
  result += days.toString();
  if (days == 1) {
    result += " day ";
  } else {
    result += " days ";
  }
}

if (hours != 0) {
  result += hours.toString();

  if (hours == 1) {
    result += " hr ";
  } else {
    result += " hrs ";
  }
}

if (minute != 0) {
  result += minute.toString();

  if (minute == 1) {
    result += " min";
  } else {
    result += " mins";
  }
}
return result;

}

Upvotes: 0

Arvind Kumar Avinash
Arvind Kumar Avinash

Reputation: 79005

Java-9 java.time Solution:

import java.time.Duration;

public class Main {
    public static void main(String[] args) {
        // Test
        System.out.println(minutesToDaysHoursMinutes(10080));
        System.out.println(minutesToDaysHoursMinutes(1600));
    }

    public static String minutesToDaysHoursMinutes(int time) {
        Duration d = Duration.ofMinutes(time);
        long days = d.toDaysPart();
        long hours = d.toHoursPart();
        long minutes = d.toMinutesPart();
        return String.format("%d Day(s) %d Hour(s) %d Minute(s)", days, hours, minutes);
    }
}

Output:

7 Day(s) 0 Hour(s) 0 Minute(s)
1 Day(s) 2 Hour(s) 40 Minute(s)

Java-8 java.time Solution:

import java.time.Duration;

public class Main {
    public static void main(String[] args) {
        // Test
        System.out.println(minutesToDaysHoursMinutes(10080));
        System.out.println(minutesToDaysHoursMinutes(1600));
    }

    public static String minutesToDaysHoursMinutes(int time) {
        Duration d = Duration.ofMinutes(time);
        long days = d.toDays();
        long hours = d.toHours() % 24;
        long minutes = d.toMinutes() % 60;
        return String.format("%d Day(s) %d Hour(s) %d Minute(s)", days, hours, minutes);
    }
}

Output:

7 Day(s) 0 Hour(s) 0 Minute(s)
1 Day(s) 2 Hour(s) 40 Minute(s)

Learn about the modern date-time API from Trail: Date Time.

Upvotes: 7

Ofer Gal
Ofer Gal

Reputation: 883

(time / 24 / 60).toFixed(0) + ":" +(time / 60 % 24).toFixed(0) + ':' + (time % 60) Does it best

Upvotes: 0

Ronny Shibley
Ronny Shibley

Reputation: 2155

1 day 2 hrs 5 mins

public static String convertToDaysHoursMinutes(long minutes) {

    int day = (int)TimeUnit.MINUTES.toDays(minutes);
    long hours = TimeUnit.MINUTES.toHours(minutes) - (day *24);
    long minute = TimeUnit.MINUTES.toMinutes(minutes) - (TimeUnit.MINUTES.toHours(minutes)* 60);

    String result = "";

    if (day != 0){
        result += day;
        if (day == 1){
            result += " day ";
        }
        else{
            result += " days ";
        }
    }

    if (hours != 0){
        result += hours;

        if (hours == 1){
            result += " hr ";
        }
        else{
            result += " hrs ";
        }
    }

    if (minute != 0){
        result += minute;

        if (minute == 1){
            result += " min";
        }
        else{
            result += " mins";
        }
    }

    return result;
}

Upvotes: 3

Kathy
Kathy

Reputation: 419

const convertMinutesToDays = (minutes) => {
    let hours
    let days 
    let restMinutes
    const onedayMinutes = 1440 //24*60

    if(minutes < 60){
        return `${minutes} Minutes` 
    }else if(minutes > 60 && minutes < onedayMinutes){
        hours = Math.floor(minutes/60)
        restMinutes = minutes%60
        return `${hours} Hours ${restMinutes} Minutes`
    }else{
        days = Math.floor((minutes/60)/24)
        restMinutes = minutes % onedayMinutes
        hours = Math.floor(restMinutes/60) 
        restMinutes = restMinutes % 60
        return `${days} Days ${hours} Hours ${restMinutes} Minutes`
    }
}

Upvotes: 0

NAVIN ROY
NAVIN ROY

Reputation: 171

for best readability ,like it won't print 0 day or 0 hour or 0 minute. e.g- (if minute=1500,then it will print only 1 day 1 hour)

int minute=150;

    StringBuilder sb=new StringBuilder();

    int day=minute/1440;
    int rem=minute%1440;
    int hour=rem/60;
    int Minute=rem%60;

if(day>0)
        sb.append(day+" day ");

if(hour>0)
        sb.append(hour+" hour ");

if(Minute>0)
        sb.append(Minute+" minute");

    System.out.println(sb);

Upvotes: 0

Durgesh Pal
Durgesh Pal

Reputation: 695

class time{
    public static void main (String args[]){
        System.out.println("Hello");
        int duration=1500;
         String testDuration = "";

        if(duration < 60){
            testDuration = duration + " minutes";
        }
        else{

            if((duration / 60)<24)
            {
                if((duration%60)==0){
                    testDuration = (duration / 60) + " hours";
                }
                else{
            testDuration = (duration / 60) + " hours," + (duration%60) + " minutes";
                }
            }
            else{

                if((duration%60)==0){
                    if(((duration/60)%24)==0){
                        testDuration = ((duration / 24)/60) + " days,";

                    }
                    else{
                    testDuration = ((duration / 24)/60) + " days," + (duration/60)%24 +"hours";
                    }
                }
                    else{
                testDuration = ((duration / 24)/60) + " days," + (duration/60)%24 +"hours"+ (duration%60) + " minutes";
                    }
            }
        }

        System.out.println(testDuration);
    }
}

Upvotes: 0

jaspreet singh
jaspreet singh

Reputation: 1

i am using this code. it can also help.

private String getText(int minutes){

    int weeks = minutes / 10080;
    int aboveWeeks = minutes % 10080;
    int days = aboveWeeks / 1440;
    int aboveDays = aboveWeeks % 1440;
    int hours = aboveDays / 60;
    int aboveHours = aboveDays % 60;
    int minute = aboveHours / 60;

    if(weeks > 0 && days > 0) {
        if(weeks > 1 && days > 1){
            return weeks + " weeks " + days + " days before";
        } else {
            return weeks + " weeks " + days + " day before";
        }
    } else if (weeks > 0){
        if (weeks > 1){
            return weeks + " weeks before";
        } else {
            return weeks + " week before";
        }
    } else if(days > 0 && hours > 0){
        if(days > 1 && hours > 1){
            return days + " days " + hours + " hours before";
        } else {
            return days + " days " + hours + " hour before";
        }
    } else if(days > 0){
        if (days > 1){
            return days + " days before";
        } else {
            return days + " day before";
        }
    } else if(hours > 0 && minute > 0){
        if(hours > 1 && minute > 1){
            return hours + " hours " + minute + " minutes before";
        } else {
            return hours + " hours " + minute + " minute before";
        }
    } else if(hours > 0){
        if (hours > 1){
            return hours + " hours before";
        } else {
            return hours + " hour before";
        }
    } else {
        if (minutes > 1){
            return minutes + " minutes before";
        } else {
            return minutes + " minute before";
        }
    }
}

Upvotes: 0

Romain Hippeau
Romain Hippeau

Reputation: 24375

If you want to do this yourself, go the other way.

  1. Divide the number by 60 * 24. (That will get the number of days.)
  2. Divide the remainder by 60. (That will give you number of hours.)
  3. The remainder of #2 is the number of minutes.

Upvotes: 17

Loren Pechtel
Loren Pechtel

Reputation: 9083

1) Your code is repetitive. This is a sign of bad code in my opinion.

2) The divisor shouldn't be changing with the number of days, because the number of days has little to do with the number of minutes in an hour.

Beyond that, look at Romain Hippeau's approach, he told you how to do it.

Upvotes: 4

Eddinho
Eddinho

Reputation: 1369

and the answer is :

 public String timeConvert(int time){
   String t = "";

  int j = time/(24*60);
  int h= (time%(24*60)) / 60;
  int m = (time%(24*60)) % 60;



   t =j + ":" + h + ":" + m;
   return t;
 }

what do you think about this code?

Upvotes: 5

Peter Lawrey
Peter Lawrey

Reputation: 533472

A shorter way. (Assumes time >= 0)

 public String timeConvert(int time) { 
   return time/24/60 + ":" + time/60%24 + ':' + time%60;
 }

Upvotes: 42

Eyal Schneider
Eyal Schneider

Reputation: 22446

If you use Java 6, TimeUnit enum can be useful. For example:

TimeUnit.HOURS.convert(10, TimeUnit.DAYS)

This static call converts 10 days into hour units, and returns 240. You can play with time units starting from NANOSECONDS and ending with DAYS.

Actually TimeUnit is available from Java 5, but in version 6 more units were added.

--EDIT-- Now that I understand better your question, use the division and remainder approach as in the response of Romain. My tip is useful only for conversion to a single time unit.

Upvotes: 12

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