Reputation: 11
I have to write a function, s(x) = x * sin(3/x) in python that is capable of taking single values or vectors/arrays, but I'm having a little trouble handling the cases when x is zero (or has an element that's zero). This is what I have so far:
def s(x):
result = zeros(size(x))
for a in range(0,size(x)):
if (x[a] == 0):
result[a] = 0
else:
result[a] = float(x[a] * sin(3.0/x[a]))
return result
Which...doesn't work for x = 0. And it's kinda messy. Even worse, I'm unable to use sympy's integrate function on it, or use it in my own simpson/trapezoidal rule code. Any ideas?
When I use integrate()
on this function, I get the following error message: "Symbol" object does not support indexing.
Upvotes: 0
Views: 908
Reputation: 91620
If you want to use SymPy's integrate, you need a symbolic function. A wrong value at a point doesn't really matter for integration (at least mathematically), so you shouldn't worry about it.
It seems there is a bug in SymPy that gives an answer in terms of zoo
at 0, because it isn't using limit
correctly. You'll need to compute the limits manually. For example, the integral from 0 to 1:
In [14]: res = integrate(x*sin(3/x), x)
In [15]: ans = limit(res, x, 1) - limit(res, x, 0)
In [16]: ans
Out[16]:
9⋅π 3⋅cos(3) sin(3) 9⋅Si(3)
- ─── + ──────── + ────── + ───────
4 2 2 2
In [17]: ans.evalf()
Out[17]: -0.164075835450162
Upvotes: 0
Reputation: 52049
This takes about 30 seconds per integrate
call:
import sympy as sp
x = sp.Symbol('x')
int2 = sp.integrate(x*sp.sin(3./x),(x,0.000001,2)).evalf(8)
print int2
int1 = sp.integrate(x*sp.sin(3./x),(x,0,2)).evalf(8)
print int1
The results are:
1.0996940
-4.5*Si(zoo) + 8.1682775
Clearly you want to start the integration from a small positive number to avoid the problem at x = 0.
You can also assign x*sin(3./x)
to a variable, e.g.:
s = x*sin(3./x)
int1 = sp.integrate(s, (x, 0.00001, 2))
My original answer using scipy to compute the integral:
import scipy.integrate
import math
def s(x):
if abs(x) < 0.00001:
return 0
else:
return x*math.sin(3.0/x)
s_exact = scipy.integrate.quad(s, 0, 2)
print s_exact
See the scipy docs for more integration options.
Upvotes: 1