Reputation:
I have been looking around and trying for a few days, but i just cant seem to get it 100% right... i am trying to achieve the following effect with css3 gradient:
the closest i have gotten is DEMO:
html {
background:
linear-gradient(80deg, transparent 50%, #ddd 50%, #ddd),
linear-gradient(90deg, transparent 50%, #ddd 50%, #ddd),
linear-gradient(82deg, transparent 50%, #eee 50%, #eee),
linear-gradient(67deg, transparent 50%, #ddd 50%, #ddd),
linear-gradient(52deg, transparent 50%, #eee 50%, #eee),
linear-gradient(37deg, transparent 50%, #ddd 50%, #ddd),
linear-gradient(22deg, transparent 50%, #eee 50%, #eee),
linear-gradient(7deg, transparent 50%, #ddd 50%, #ddd),
linear-gradient(-8deg, transparent 50%, #eee 50%, #eee),
linear-gradient(-23deg, transparent 50%, #ddd 50%, #ddd),
linear-gradient(-38deg, transparent 50%, #eee 50%, #eee),
linear-gradient(-53deg, transparent 50%, #ddd 50%, #ddd),
linear-gradient(-68deg, transparent 50%, #eee 50%, #eee),
linear-gradient(-83deg, transparent 50%, #ddd 50%, #ddd);
background-position: center -100%;
background-color: #eee;
background-size: 100% 200%;
min-height: 100%;
}
I will continue attempting it.. any help is greatly Appreciated though.
Update:
There has to be a better/reusable way of doing this... looking into a scss solution, here is what i have thus far:
.sunburst {
@for $ray from 1 through 26 {
$color: #eee;
$degree: 7;
@if $ray%2 == 0 {
$color: #ddd;
}
background:linear-gradient($degree+deg, transparent 50%, $color 50%, $color),
}
}
Now its just the actual maths behind it i am trying to figure out... attempting to steal logic from pow.js, but kind of difficult if your as terrible at maths as i am...
Upvotes: 7
Views: 6306
Reputation: 8551
Currently, there is a repeating-conic-gradient
, which creates an image consisting of a repeating gradient.
div {
height: 500px;
background: repeating-conic-gradient(
hsl(186deg 100% 50% / 31%) 0deg 15deg,
hsla(0,0%,100%,0) 0deg 30deg
) #1c2c3c
}
<div></div>
You read more about it at W3 CSS Image Values.
This property is not compatible with all browsers. Check caniuse for more information.
Upvotes: 0
Reputation: 2427
In modern chrome-based browsers there are conic gradients which do this.
div {
height:250px;
background-image:
repeating-conic-gradient(#fff 0 9deg, #000 9deg 18deg);
}
<div></div>
Upvotes: 5
Reputation: 13848
@chipChocolate.py gave a brilliant solution! This is an improvement based on his.
In Firefox transparent
behaves like rgba(0,0,0,0)
which leaves a thin gray line at the edge. Change to rgba(255,255,255,0)
looks better.
Make the visual effect closer to OP's screenshot: 36 strips, each occupies a 10 degree angle.
Effective on <html>
tag, like OP's try.
BTW: Chrome's render engine sucks, best viewed in Firefox.
html {
height: 100%;
position: relative;
}
html:before, html:after {
content: '';
height: 100%;
width: 50%;
position: absolute;
top: 0;
background-size: 200% 100%;
background-image: linear-gradient(85deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db),
linear-gradient(75deg, rgba(255,255,255,0) 50%, #000 50%, #000),
linear-gradient(65deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db),
linear-gradient(55deg, rgba(255,255,255,0) 50%, #000 50%, #000),
linear-gradient(45deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db),
linear-gradient(35deg, rgba(255,255,255,0) 50%, #000 50%, #000),
linear-gradient(25deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db),
linear-gradient(15deg, rgba(255,255,255,0) 50%, #000 50%, #000),
linear-gradient(5deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db),
linear-gradient(-5deg, rgba(255,255,255,0) 50%, #000 50%, #000),
linear-gradient(-15deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db),
linear-gradient(-25deg, rgba(255,255,255,0) 50%, #000 50%, #000),
linear-gradient(-35deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db),
linear-gradient(-45deg, rgba(255,255,255,0) 50%, #000 50%, #000),
linear-gradient(-55deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db),
linear-gradient(-65deg, rgba(255,255,255,0) 50%, #000 50%, #000),
linear-gradient(-75deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db),
linear-gradient(-85deg, rgba(255,255,255,0) 50%, #000 50%, #000),
linear-gradient(-95deg, rgba(255,255,255,0) 50%, #12e0db 50%, #12e0db);
}
html:before {
left: 50%;
transform: rotate(180deg);
}
Upvotes: 0
Reputation: 22992
You could use :before
and :after
:pseudo-elements to get this effect.
html, body {
width: 100%;
height: 100%;
margin: 0;
}
#grad {
position: relative;
width: 100%;
height: 100%;
}
#grad:after, #grad:before {
content: '';
position: absolute;
background: linear-gradient(90deg, transparent 50%, black 50%, black), linear-gradient(82deg, transparent 50%, #12E0DB 50%, #12E0DB), linear-gradient(67deg, transparent 50%, #000000 50%, #000000), linear-gradient(52deg, transparent 50%, #12E0DB 50%, #12E0DB), linear-gradient(37deg, transparent 50%, #000000 50%, #000000), linear-gradient(22deg, transparent 50%, #12E0DB 50%, #12E0DB), linear-gradient(7deg, transparent 50%, #000000 50%, #000000), linear-gradient(-8deg, transparent 50%, #12E0DB 50%, #12E0DB), linear-gradient(-23deg, transparent 50%, #000000 50%, #000000), linear-gradient(-38deg, transparent 50%, #12E0DB 50%, #12E0DB), linear-gradient(-53deg, transparent 50%, #000000 50%, #000000), linear-gradient(-68deg, transparent 50%, #12E0DB 50%, #12E0DB), linear-gradient(-83deg, transparent 50%, #000000 50%, #000000), linear-gradient(-90deg, transparent 50%, #12E0DB 50%, #12E0DB);
background-position: 0% 0%;
background-size: 200% 100%;
height: 100%;
width: 50%;
}
#grad:before {
left: 50%;
transform: rotate(180deg);
}
<div id="grad"></div>
Upvotes: 5
Reputation: 3074
your background-postition
is set to center -100%;
. Just use
background-position: center center;
Now with this change and your provided code half of your image is already done ;). Just add the second half with more linear-gradients
Upvotes: 0