CODEWITHSUNDEEP
c++macrosc-preprocessor
rabidmachine9
rabidmachine9

Reputation: 7985

C++ macros explanation

Can somebody explain the following code please?

#if 1

// loop type
#define FOR_IS_FASTER 1
#define WHILE_IS_FASTER 0
// indexing type
#define PREINCREMENT_IS_FASTER 1
#define POSTINCREMENT_IS_FASTER 0

#else

// loop type
#define FOR_IS_FASTER 1
#define WHILE_IS_FASTER 0
// indexing type
#define PREINCREMENT_IS_FASTER 0
#define POSTINCREMENT_IS_FASTER 1

#endif


#if PREINCREMENT_IS_FASTER
#define ZXP(z) (*++(z))
#define ZX(z) (*(z))
#define PZ(z) (++(z))
#define ZP(z) (z)
#define ZOFF (1)
#elif POSTINCREMENT_IS_FASTER
#define ZXP(z) (*(z)++)
#define ZX(z) (*(z))
#define PZ(z) (z)
#define ZP(z) ((z)++)
#define ZOFF (0)
#endif

I can understand what the functions are doing but for example how does the pre-processor choose which ZXP will be execute if we call it later? What do the 1 and 0 stand for?

Upvotes: 0

Views: 165

Answers (2)

Puppy
Puppy

Reputation: 147028

I'm probably inclined to agree with UncleBens and suggest that it's done so that you don't understand it, because the whole lot is totally useless.

Upvotes: 1

Marcelo Cantos
Marcelo Cantos

Reputation: 186078

The #if 1 triggers the first group of #defines, which set PREINCREMENT_IS_FASTER to 1. Because of this, #if PREINCREMENT_IS_FASTER triggers the first #define ZXP....

There is nothing exceptional about 1 and 0 in this context. The #if preprocessor directive succeeds if its argument is non-zero.

You can switch to the alternate form by changing the #if 1 at the top of the file with #if 0. (Thank you @rabidmachine for the tip.)

Upvotes: 6

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