CODEWITHSUNDEEP
lua
laws16
laws16

Reputation: 53

What's wrong with this lua script

RPS = {}
RPS[1] = "Rock"
RPS[2] = "Paper"
RPS[3] = "Scissors"
function RPS()
    playerOne = math.random( #RPS ) 
    playerTwo = math.random( #RPS )

    if playerOne == playerTwo then
        print("It is a tie\n Player One played "..playerOne.."\n Player Two played "..playerTwo..)
    elseif playerOne == RPS[1] then
        if playerTwo == RPS[2] then
            print("Player Two wins\n Player One played "..playerOne.."\n Player Two played "..playerTwo..)
        else
            print("Player One wins\n Player One played "..playerOne.."\n Player Two played "..playerTwo..)
        end
    elseif playerOne == RPS[2] then
        if playerTwo == RPS[1] then
            print("Player One wins\n Player One played "..playerOne.."\n Player Two played "..playerTwo..)
        else
            print("Player Two wins\n Player One played "..playerOne.."\n Player Two played "..playerTwo..)
        end
    else
        if playerTwo == RPS[1] then
            print("Player Two wins\n Player One played "..playerOne.."\n Player Two played "..playerTwo..)
        else
            print("Player One wins\n Player One played "..playerOne.."\n Player Two played "..playerTwo..)
        end
    end
end
print(RPS())

Don't know what's wrong with this script, appreciate some input from you guys. Although the error says on line 19:

    print("Player One wins\n Player One played "..playerOne.."\n Player Two played "..playerTwo..)

That there is an expected near ')'

Upvotes: 2

Views: 1077

Answers (1)

meyer9
meyer9

Reputation: 1140

There is a concatenation call (..) at the end, but it only has one argument. Delete that and that should fix the error. Remember that concatenation means adding two strings together and it must have two arguments.

print("Player One wins\n Player One played "..playerOne.."\n Player Two played "..playerTwo)

You also need to change the table name or the function name since they are conflicting.

Upvotes: 6

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