Reputation: 1244
I have two points on my form, and a picturebox, like this:
*
[^]
[ ]
*
I would like to align the picturebox with the points, so that it looks like this:
*
\^\
\ \
*
How would I calculate the angle and how would I rotate the PictureBox?
Currently I'm using this:
double xDifference = Math.Abs(point2.X - point1.X);
double yDifference = Math.Abs(point2.Y - point1.Y);
double angle = Math.Atan(yDifference / xDifference) * 180 / Math.PI;
But that doesn't work since the x and y values are absolute, and thus they can't calculate it if point 2 is left of point 1.
To rotate the image, I found the following function:
public Bitmap rotateImage(Image image, PointF offset, float angle) {
// Create a new empty bitmap to hold rotated image
Bitmap rotatedBmp = new Bitmap(image.Width, image.Height);
rotatedBmp.SetResolution(image.HorizontalResolution, image.VerticalResolution);
// Make a graphics object from the empty bitmap
Graphics g = Graphics.FromImage(rotatedBmp);
// Put the rotation point in the center of the image
g.TranslateTransform(offset.X, offset.Y);
// Rotate the image
g.RotateTransform(angle);
// Move the image back
g.TranslateTransform(-offset.X, -offset.Y);
// Draw passed in image onto graphics object
g.DrawImage(image, new PointF(0, 0));
return rotatedBmp;
}
How would I use that function? I'm not sure what values to insert for offset.
Thanks
Upvotes: 7
Views: 1234
Reputation: 8359
I do not like to use angle when it is not necessary.
Here, you just want to change of orthonormal basis.
From {X;Y} you want to move to {U;V} where V (of norm 1) is parallel to AB (or point1 point2).
Because {U;V} is an orthonormal basis, Ux = Vy and Uy = -Vx.
using System;
using System.Drawing;
using System.Drawing.Drawing2D;
using System.Windows.Forms;
namespace CsiChart
{
public partial class CustomControl1 : Control
{
private const float EPSILON = 1e-6f;
private Image _image;
private ImageLayout _imageLayout = ImageLayout.Center;
private PointF _pointA = new PointF(0, 100);
private PointF _pointB = new PointF(100, 0);
public CustomControl1()
{
InitializeComponent();
}
public Image Image
{
get { return _image; }
set
{
if (Equals(_image, value)) return;
_image = value;
Invalidate();
OnImageChanged(EventArgs.Empty);
}
}
public event EventHandler ImageChanged;
public ImageLayout ImageLayout
{
get { return _imageLayout; }
set
{
if (Equals(_imageLayout, value)) return;
_imageLayout = value;
Invalidate();
OnImageLayoutChanged(EventArgs.Empty);
}
}
public event EventHandler ImageLayoutChanged;
public PointF PointA
{
get { return _pointA; }
set
{
if (Equals(_pointA, value)) return;
_pointA = value;
Invalidate();
OnPointAChanged(EventArgs.Empty);
}
}
public event EventHandler PointAChanged;
public PointF PointB
{
get { return _pointB; }
set
{
if (Equals(_pointB, value)) return;
_pointB = value;
Invalidate();
OnPointBChanged(EventArgs.Empty);
}
}
public event EventHandler PointBChanged;
protected override void OnPaint(PaintEventArgs pe)
{
base.OnPaint(pe);
if (DesignMode) return;
var g = pe.Graphics;
g.Clear(BackColor);
var image = Image;
if (image == null) return;
var clientRectangle = ClientRectangle;
var centerX = clientRectangle.X + clientRectangle.Width / 2;
var centerY = clientRectangle.Y + clientRectangle.Height / 2;
var srcRect = new Rectangle(new Point(0, 0), image.Size);
var pointA = PointA;
var pointB = PointB;
// Compute U, AB vector normalized.
var vx = pointB.X - pointA.X;
var vy = pointB.Y - pointA.Y;
var vLength = (float) Math.Sqrt(vx*vx + vy*vy);
if (vLength < EPSILON)
{
vx = 0;
vy = 1;
}
else
{
vx /= vLength;
vy /= vLength;
}
var oldTransform = g.Transform;
// Change basis to U,V
// We also take into acount the inverted on screen Y.
g.Transform = new Matrix(-vy, vx, -vx, -vy, centerX, centerY);
var imageWidth = image.Width;
var imageHeight = image.Height;
RectangleF destRect;
switch (ImageLayout)
{
case ImageLayout.None:
destRect = new Rectangle(0, 0, imageWidth, imageHeight);
break;
case ImageLayout.Center:
destRect = new Rectangle(-imageWidth/2, -imageHeight/2, imageWidth, imageHeight);
break;
case ImageLayout.Zoom:
// XY aligned bounds size of the image.
var imageXSize = imageWidth*Math.Abs(vy) + imageHeight*Math.Abs(vx);
var imageYSize = imageWidth*Math.Abs(vx) + imageHeight*Math.Abs(vy);
// Get best scale to fit.
var s = Math.Min(clientRectangle.Width/imageXSize, clientRectangle.Height/imageYSize);
destRect = new RectangleF(-imageWidth*s/2, -imageHeight*s/2, imageWidth*s, imageHeight*s);
break;
default:
throw new InvalidOperationException();
}
g.DrawImage(image, destRect, srcRect, GraphicsUnit.Pixel);
g.Transform = oldTransform;
}
protected virtual void OnImageChanged(EventArgs eventArgs)
{
var handler = ImageChanged;
if (handler == null) return;
handler(this, eventArgs);
}
protected virtual void OnImageLayoutChanged(EventArgs eventArgs)
{
var handler = ImageLayoutChanged;
if (handler == null) return;
handler(this, eventArgs);
}
private void OnPointAChanged(EventArgs eventArgs)
{
var handler = PointAChanged;
if (handler == null) return;
handler(this, eventArgs);
}
private void OnPointBChanged(EventArgs eventArgs)
{
var handler = PointBChanged;
if (handler == null) return;
handler(this, eventArgs);
}
}
}
Upvotes: 3
Reputation: 35594
Let's put all the computations together.
First of all, the direction of the line connecting the two points can be computed by
double xDifference = point2.X - point1.X;
double yDifference = point2.Y - point1.Y;
double angleRadians = Math.Atan2(yDifference, xDifference);
Then, the vertical direction (90 degrees) must be parallel to the direction considered above after the rotation, so the rotation angle is
double rotationAngleRadians = angleDegrees - Math.PI/2;
Having this angle, we can compute the bounding box's size:
double newWidth = image.Width * Math.Abs(Math.Cos(rotationAngleRadians)) +
image.Height * Math.Abs(Math.Sin(rotationAngleRadians));
double newHeight = image.Width * Math.Abs(Math.Sin(rotationAngleRadians)) +
image.Height * Math.Abs(Math.Cos(rotationAngleRadians));
Now, we need first to transform in such a way that the middle of the old image is at position 0. This makes translate transform by (-image.Width/2, -image.Height/2)
. Then, we apply rotation by the rotationAngleDegrees
(which is rotationAngleRadians * 180 / Math.PI
), as Graphics
' rotation expects angle in degrees. Then, we shift the image to be in the middle of the new image, that is translate transform by (newWidth/2, newHeight/2)
.
Upvotes: 2