CODEWITHSUNDEEP
javabytebufferunsigned-integer
user2947084
user2947084

Reputation: 37

Inserting unsigned integer value into bytebuffer, maintaining binary representation

I'm trying to put the following binary representation into a bytebuffer for 4 bytes. But since Java doesn't do unsigned, I'm having trouble: 11111111000000001111111100000000

ByteBuffer bb = ByteBuffer.allocate(8);

bb.putInt(Integer.parseInt("11111111000000001111111100000000", 2));
//throws numberformatexception

Negating the most significant bit seems to change the binary string value because of how two's compliment works:

bb.putInt(Integer.parseInt("-1111111000000001111111100000000", 2));
System.out.println(Integer.toBinaryString(bb.getInt(0)));
//prints 10000000111111110000000100000000

It's important that the value is in this binary format exactly because later it will be treated as an unsigned int. How should I be adding the value (and future values that start with 1) to the bytebuffer?

Upvotes: 1

Views: 1227

Answers (3)

Jon Skeet
Jon Skeet

Reputation: 1503220

Just parse it as a long first, and cast the result:

int value = (int) Long.parseLong("11111111000000001111111100000000", 2);

That handles the fact that int runs out of space, because there's plenty of room in a long. After casting, the value will end up as a negative int, but that's fine - it'll end up in the byte buffer appropriately.

EDIT: As noted in comments, in Java 8 you can use Integer.parseUnsignedInt("...", 2).

Upvotes: 1

Jean Logeart
Jean Logeart

Reputation: 53849

You can also use Guava's UnsignedInts.parseUnsignedInt(String string, int radix) and UnsignedInts.toString(int x,int radix) methods:

int v = UnsignedInts.parseUnsignedInt("11111111000000001111111100000000", 2);
System.out.println(UnsignedInts.toString(v, 2));

Upvotes: 1

Evgeniy Dorofeev
Evgeniy Dorofeev

Reputation: 136102

try this

    bb.putInt((int)Long.parseLong("11111111000000001111111100000000", 2));

Upvotes: 0

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