CODEWITHSUNDEEP
pythondate
Harr Tou
Harr Tou

Reputation: 41

Given Date, Asked to print the next date

date = raw_input()
while date!="END" or date!="end":
    day  = date[0:2]
    month = date[3:5]
    monthsingle = date[3:5]
    monthsingle =str(int(monthsingle))
    monthsingle = int(monthsingle)

What I am trying to accomplish here is assign the month's number to monthsingle to use it later in my code. The problem is the user is allowed to type "02" for February. How can I do this without this error:

monthsingle =str(int(monthsingle))
ValueError: invalid literal for int() with base 10: ''

Upvotes: 0

Views: 6383

Answers (5)

Ashok Kumar
Ashok Kumar

Reputation: 59

Solution in Java

Implement a program to generate and display the next date of a given date. The date will be provided as day, month and year as shown in the below table. The output should be displayed in the format: day-month-year. Assumption: The input will always be a valid date.

class NextDate 
{
    public static void main(String[] args) 
    {
        // Implement your code here 
        int day = 31,month = 12, year=15,monthLength;
        year = 2000+year;
        char leap;
        
        if((year % 4==0) & (year % 100 == 0) || (year % 400 == 0))
        {
            leap = 'y';
        }
        else
        {
            leap = 'n';
        }

        if(month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12)
        {
            monthLength = 31;
        }
        else if(month == 2)
        {
            if(leap == 'y')
            {
                monthLength = 28;
            }
            else
            {
                monthLength = 29;
            }
            
        }
        else
        {
            monthLength = 30;
        }
        
        if(day < monthLength)
        {
            day++;
        }
        else if(month == 12 & day == monthLength)
        {
            day = 1;
            month=1;
            year++;
        }
        System.out.println(day+"-"+month+"-"+year);
    }
}

Upvotes: -1

Ash15
Ash15

Reputation: 25

def generate_next_date(day,month,year):
    #Start writing your code here
    if((year%400==0 or year%4==0) and month==2):
        next_day=day+1
        next_month=month
        next_year=year
    elif(month==2 and day==28):
        next_day=1
        next_month=month+1
        next_year=year
    elif(month==12 and day==31):
        next_day=1
        next_month=1
        next_year=year+1
    elif(day==31 ):
        next_day=1
        next_month=month+1
        next_year=year
    elif((day==30) and (month==4 or month==6 or month==9 or month==11)):
        next_day=1
        next_month=month+1
        next_year=year
    else:
        next_day=day+1
        next_month=month
        next_year=year




    print(next_day,"-",next_month,"-",next_year)


generate_next_date(28,2,2015)

Upvotes: -1

jfs
jfs

Reputation: 414079

It is not a problem that the user is allowed to type 02 for February. The error message indicates that the issue is that monthsingle is empty (''). If you slice a string beyond its end; you get an empty string. It means that the input is not in dd/mm format.

To parse the date without using datetime.strptime() function:

while True:
    try:
        day, month = map(int, raw_input("Enter date dd/mm: ").split('/'))
        # validate day, month here...
    except ValueError:
        print 'invalid input, try again'
    else:
        break

# use day, month to get the next date...
# you could use datetime module to check your answer:
from datetime import date, timedelta
print(date(date.today().year, month, day) + timedelta(1))

Upvotes: 0

H&#229;ken Lid
H&#229;ken Lid

Reputation: 23064

If the user input is less than four characters long, date[3:5] will be the empty string.

You could check that the input string is valid before trying to convert it to an integer, or catch the exception and give the user a helpful error message. Unexpected user input should not cause your program to crash.

while True:
    print('Please enter a date in format "dd/mm" or "end".')
    date = raw_input()  # use input() if you use python 3
    if date.lower() == 'end':
        print('good bye')
        break
    try:
        day = int(date[0:2])
        month = int(date[3:5])
        print('Day is %d and month is %d' % (day, month))
        # Day and month are integers. 
        # You should check that it's a real date as well.
    except ValueError:
        # could not convert to integer
        print('invalid input!')

Upvotes: 1

yesenin
yesenin

Reputation: 199

In this implementation you can trim '0' at the begining:

monthsingle = date[3:5].lstrip('0')

Or check date[3:5]: it seems like there is a dot.

Upvotes: 0

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