CODEWITHSUNDEEP
pythonpython-3.x
Zach Gates
Zach Gates

Reputation: 4155

How do I check a string for any number?

I have a string similar to this:

string = '(1:[0,0,0]; 2:[21,0,12])'

Except my string goes on for thousands of numbers.

... '4214:[9,93,42])'

How do I select the number, colon, and opening bracket? Like this:

'1:['
'2:['
'2831:['
'4214:['

I want to select each one of these and replace it with a new string: '('.

Upvotes: 0

Views: 67

Answers (2)

ssm
ssm

Reputation: 5383

Your data is already in the form of a dictioanry. Just do the following: 

In [35]: xx = eval(string.replace(";", ',').replace('(', '{').replace(')', '}'))

The result is a dictionary ...

In [36]: xx.keys()
Out[36]: [1, 2]

In [37]: xx[2]
Out[37]: [21, 0, 12]

Upvotes: 1

Rufflewind
Rufflewind

Reputation: 8966

You could use a regular expression:

new_string = re.replace(r'[0-9]+:\[', r'\(', string)

This replaces all occurences of <number>:[ with (.

Upvotes: 4

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