damnpoet
damnpoet

Reputation: 223

Visual Studio loading the right (x86 or x64) dll

I'm working on Visual Studio in an x86. I would like to build my application for both x32 and x64. But I need to use the sqlite .net connector which has a dll for x86 apps and another dll for x64 apps.

How do I configure my Visual Studio to load a reference when my configuration is x64 and another when my configuration is x86?

Upvotes: 22

Views: 7592

Answers (3)

Ron
Ron

Reputation: 1998

This slightly simpler answer than Preet Sangha's will not generate a warning when the project is loaded and only the conditionally accepted dll will appear in the Solution Explorer. So, overall, the appearance is cleaner, although more subtle. (This was tested in Visual Studio 2010.)

<Reference Include="p4dn" Condition="$(Platform) == 'x86'">
  <HintPath>..\..\ThirdParty\P4.Net\clr4\x86\p4dn.dll</HintPath>
</Reference>
<Reference Include="p4dn" Condition="$(Platform) == 'x64'">
  <HintPath>..\..\ThirdParty\P4.Net\clr4\x64\p4dn.dll</HintPath>
</Reference>

Upvotes: 10

antsyawn
antsyawn

Reputation: 981

You can also build your application for "Any CPU" and dynamically choose which DLL to load.

Upvotes: 0

Preet Sangha
Preet Sangha

Reputation: 65506

in your project file in reference use an MSBUILD conditional

<Reference 
       Include="SomeAssembly86, Version=0.85.5.452, Culture=neutral, PublicKeyToken=41b332442f1101cc, processorArchitecture=MSIL"  
         Condition=" '$(Platform)' == 'AnyCPU' ">
      <SpecificVersion>False</SpecificVersion>
      <HintPath>..\..\Dependencies\SomeAssembly.dll</HintPath>
      <Private>False</Private>
    </Reference>
    <Reference 
         Include="SomeOtherAssembly, Version=0.85.5.999, Culture=neutral, PublicKeyToken=41b332442f1101cc, processorArchitecture=MSIL" 
         Condition=" '$(Platform)' == 'x64' ">
      <SpecificVersion>False</SpecificVersion>
      <HintPath>..\..\Dependencies\SomeOtherAssembly.dll</HintPath>
      <Private>False</Private>
    </Reference>

Upvotes: 23

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