CODEWITHSUNDEEP
pythonstring-formatting
systempuntoout
systempuntoout

Reputation: 74134

How to print the sign + of a digit for positive numbers in Python

Is there a better way to print the + sign of a digit on positive numbers?

integer1 = 10
integer2 = 5
sign = ''
total = integer1-integer2
if total > 0: sign = '+'
print 'Total:'+sign+str(total)

0 should return 0 without +.

Upvotes: 92

Views: 73728

Answers (3)

ErichBSchulz
ErichBSchulz

Reputation: 15669

From python 3.6 onwards:

>>> integer1 = 10
>>> integer2 = 5
>>> total = integer1-integer2
>>> print(f'Total: {total:+}')
Total: +5

or: 

for i in range(-1,2):
    print (f' {i} becomes {i:+}')

outputs: 

 -1 becomes -1
 0 becomes +0
 1 becomes +1

Upvotes: 43

Khelben
Khelben

Reputation: 6461

Use the new string format

>>> '{0:+} number'.format(1)
'+1 number'
>>> '{0:+} number'.format(-1)
'-1 number'
>>> '{0:+} number'.format(-37)
'-37 number'
>>> '{0:+} number'.format(37)
'+37 number'
# As the questions ask for it, little trick for not printing it on 0
>>> number = 1
>>> '{0:{1}} number'.format(number, '+' if number else '')
'+1 number'
>>> number = 0
>>> '{0:{1}} number'.format(number, '+' if number else '')
'0 number'

It's recommended over the % operator

Upvotes: 109

John Machin
John Machin

Reputation: 83002

>>> print "%+d" % (-1)
-1
>>>
>>> print "%+d" % (1)
+1
>>> print "%+d" % (0)
+0
>>>

Here is the documentation.

** Update** If for whatever reason you can't use the % operator, you don't need a function:

>>> total = -10; print "Total:" + ["", "+"][total > 0] + str(total)
Total:-10
>>> total = 0; print "Total:" + ["", "+"][total > 0] + str(total)
Total:0
>>> total = 10; print "Total:" + ["", "+"][total > 0] + str(total)
Total:+10
>>>

Upvotes: 73

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