Reputation: 485
I have a console application in C#, and I want that the user won't be able to see it.
How can I do that?
Upvotes: 30
Views: 27508
Reputation: 97
I've got a general solution to share:
using System;
using System.Runtime.InteropServices;
namespace WhateverNamepaceYouAreUsing
{
class Magician
{
[DllImport("kernel32.dll")]
static extern IntPtr GetConsoleWindow();
[DllImport("user32.dll")]
static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);
const int HIDE = 0;
const int SHOW = 5;
public static void DisappearConsole()
{
ShowWindow(GetConsoleWindow(), HIDE);
}
}
}
Just include this class in your project, and call Magician.DisappearConsole();
.
A console will flash when you start the program by clicking on it. When executing from the command prompt, the command prompt disappears very shortly after execution.
I do this for a Discord Bot that runs forever in the background of my computer as an invisible process. It was easier than getting TopShelf to work for me. A couple TopShelf tutorials failed me before I wrote this with some help from code I found elsewhere. ;P
I also tried simply changing the settings in Visual Studio > Project > Properties > Application to launch as a Windows Application instead of a Console Application, and something about my project prevented this from hiding my console - perhaps because DSharpPlus demands to launch a console on startup. I don't know. Whatever the reason, this class allows me to easily kill the console after it pops up.
Hope this Magician helps somebody. ;)
Upvotes: 1
Reputation: 999
To hide a console applicatin in C# when nothing else works use this code:
[DllImport("kernel32.dll")]
public static extern bool FreeConsole();
Place FreeConsole() anywhere in the code, I placed it in the Init(), and the commandline is hidden.
Upvotes: 2
Reputation: 3214
The best way is to start the process without window.
Process p = new Process();
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "echo Hello!";
//either..
p.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
//or..
p.StartInfo.CreateNoWindow = true;
p.Start();
See other probable solutions -
Toggle Process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden at runtime
and,
Bring another processes Window to foreground when it has ShowInTaskbar = false
Upvotes: 2
Reputation: 39916
Create a console application "MyAppProxy" with following code, and put MyAppProxy in start up dir,
public static void main(string[] args)
{
Process p = new Process("MyApp");
ProcessStartUpInfo pinfo = new ProcessStartUpInfo();
p.StartupInfo = pinfo;
pinfo.CreateNoWindow = true;
pinfo.ShellExecute = false;
p.RaiseEvents = true;
AutoResetEvent wait = new AutoResetEvent(false);
p.ProcessExit += (s,e)=>{ wait.Set(); };
p.Start();
wait.WaitOne();
}
You may need to fix certain items here as I didnt check correctness of the code, it may not compile because some property names may be different, but hope you get the idea.
Upvotes: 5
Reputation: 6360
Sounds like you don't want a console application, but a windows GUI application that doesn't open a (visible) window.
Upvotes: 5
Reputation: 164281
Compile it as a Windows Forms application. Then it won't display any UI, if you do not explicitly open any Windows.
Upvotes: 56
Reputation: 8209
You can Pinvoke a call to FindWindow() to get a handle to your window and then call ShowWindow() to hide the window OR Start your application from another one using ProcessStartInfo.CreateNoWindow
Upvotes: 1