BlueTrin
BlueTrin

Reputation: 10063

bz2 decompress with Python 3.4 - TypeError: 'str' does not support the buffer interface

There are similar errors but I could not find a solution for bz2.

The following program fails on the decompress:

import bz2

un =  'BZh91AY&SYA\xaf\x82\r\x00\x00\x01\x01\x80\x02\xc0\x02\x00 \x00!\x9ah3M\x07<]\xc9\x14\xe1BA\x06\xbe\x084'
pw =  'BZh91AY&SY\x94$|\x0e\x00\x00\x00\x81\x00\x03$ \x00!\x9ah3M\x13<]\xc9\x14\xe1BBP\x91\xf08'
decoded_un = bz2.decompress(un)
decoded_pw = bz2.decompress(pw)

print(decoded_un)
print(decoded_pw)

I tried using bytes(un, 'UTF-8) but that would not work. I think I did not have this problem in Python 3.3.

EDIT: this was for the Python challenge I have two bits of code which work thanks to Martijn:

import bz2

un_saved =  'BZh91AY&SYA\xaf\x82\r\x00\x00\x01\x01\x80\x02\xc0\x02\x00 \x00!\x9ah3M\x07<]\xc9\x14\xe1BA\x06\xbe\x084'
pw_saved =  'BZh91AY&SY\x94$|\x0e\x00\x00\x00\x81\x00\x03$ \x00!\x9ah3M\x13<]\xc9\x14\xe1BBP\x91\xf08'
print(bz2.decompress(un_saved.encode('latin1')))
print(bz2.decompress(pw_saved.encode('latin1')))

This one works from the webpage:

# http://www.pythonchallenge.com/pc/def/integrity.html

import urllib.request
import re
import os.path
import bz2

fname = "008.html"

if not os.path.isfile(fname):
    url = 'http://www.pythonchallenge.com/pc/def/integrity.html'
    response = urllib.request.urlopen(url)
    webpage = response.read().decode("utf-8")
    with open(fname, "w") as fh:
        fh.write(webpage)

with open(fname, "r") as fh:
    webpage = fh.read()
    re_un = '\\nun: \'(.*)\'\\n'
    m = re.search(re_un, webpage)
    un = m.group(1)
    print(un)

    pw_un = '\\npw: \'(.*)\'\\n'
    m = re.search(pw_un, webpage)
    pw = m.group(1)
    print(pw)

    unde = un.encode('latin-1').decode('unicode_escape').encode('latin1')
    pwde = pw.encode('latin-1').decode('unicode_escape').encode('latin1')
    decoded_un = bz2.decompress(unde)
    decoded_pw = bz2.decompress(pwde)

    print(decoded_un)
    print(decoded_pw)

Upvotes: 1

Views: 3295

Answers (1)

Martijn Pieters
Martijn Pieters

Reputation: 1121564

The bz2 library deals with bytes objects, not strings:

un = b'BZh91AY&SYA\xaf\x82\r\x00\x00\x01\x01\x80\x02\xc0\x02\x00 \x00!\x9ah3M\x07<]\xc9\x14\xe1BA\x06\xbe\x084'
pw = b'BZh91AY&SY\x94$|\x0e\x00\x00\x00\x81\x00\x03$ \x00!\x9ah3M\x13<]\xc9\x14\xe1BBP\x91\xf08'

In other words, using bytes() works just fine, just make sure you use the correct encoding. UTF-8 is not that encoding; if you have bytes masking as string character codepoints, use Latin-1 to encode instead; Latin 1 maps characters one-on-one to bytes:

un = un.encode('latin1')

or

un = bytes(un, 'latin1')

Also see the Python Unicode HOWTO:

Latin-1, also known as ISO-8859-1, is a similar encoding. Unicode code points 0–255 are identical to the Latin-1 values, so converting to this encoding simply requires converting code points to byte values; if a code point larger than 255 is encountered, the string can’t be encoded into Latin-1.

I'll leave the decoding to you. Have fun with the Python Challenge!

Note that if you loaded these characters as they are from a webpage, they will not by ready-made bytes! You'll have the characters '\', 'x', 8 and 2 rather than a codepoint with hex value 82. You'd need to interpret those sequences as a Python string literal first:

>>> un = r'BZh91AY&SYA\xaf\x82\r\x00\x00\x01\x01\x80\x02\xc0\x02\x00 \x00!\x9ah3M\x07<]\xc9\x14\xe1BA\x06\xbe\x084'
>>> un
'BZh91AY&SYA\\xaf\\x82\\r\\x00\\x00\\x01\\x01\\x80\\x02\\xc0\\x02\\x00 \\x00!\\x9ah3M\\x07<]\\xc9\\x14\\xe1BA\\x06\\xbe\\x084'
>>> un.encode('latin-1').decode('unicode_escape')
'BZh91AY&SYA¯\x82\r\x00\x00\x01\x01\x80\x02À\x02\x00 \x00!\x9ah3M\x07<]É\x14áBA\x06¾\x084'
>>> un.encode('latin-1').decode('unicode_escape').encode('latin1')
b'BZh91AY&SYA\xaf\x82\r\x00\x00\x01\x01\x80\x02\xc0\x02\x00 \x00!\x9ah3M\x07<]\xc9\x14\xe1BA\x06\xbe\x084'

Note the double backslashes in the representation of un. Only the last bytes result is then decompressable!

Upvotes: 1

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