Reputation: 1027
I want to accept in a django url:
StoreageLocation/X-YYY-X (E-152-A , E-112-B)
(where X is [A-Z]
and Y is [0-9]
)
First I tried to solve for X-YYY with:
url(r'^StorageLocation/\[A-Z\-0-9{3}])$', views.StorageLocation, name='StorageLocation'),
but that won't work. Please help.
Upvotes: 0
Views: 70
Reputation: 474221
Check one upper case letter, then dash, then exactly 3 digits, the dash and a single upper case letter:
url(r'^StorageLocation/[A-Z]\-[0-9]{3}\-[A-Z]$', views.StorageLocation, name='StorageLocation'),
Demo:
>>> import re
>>> pattern = re.compile(r'[A-Z]\-[0-9]{3}\-[A-Z]')
>>> pattern.match('E-152-A')
<_sre.SRE_Match object at 0x103aba6b0>
>>> pattern.match('E-112-B')
<_sre.SRE_Match object at 0x103abab90>
Upvotes: 1