CODEWITHSUNDEEP
phpfunction
user3356666
user3356666

Reputation: 39

function doesn't work (doesn't print anything)

I have make function but it doesn't want to work , I don't know why or what the wrong because I think all is good

function  ifemptySet($who,$set){
   if(empty($who)){
       $who = "$set";   
   }
}


if(isset($_POST['saveinfosite'])){
   $site_name = strip_tags($_POST['site_name']);


   ifemptySet($site_name,"null");


   echo $site_name;




  }

When I set the " input " empty , php (echo) doesn't print anything , but when I write something in the "input" , I show only what I have put in the Input

(Sorry for my english)

Upvotes: 0

Views: 108

Answers (2)

Rizier123
Rizier123

Reputation: 59681

You just have to change your function header to this:

function  ifemptySet(&$who,$set){
                   //^See here! Passed by reference 
   if(empty($who)){
       $who = "$set";   
   }
}

Also you could do it with return like this:

function  ifemptySet($who,$set){
   if(empty($who)){
       return $who = "$set";   
   }
   return $who;
}

For more information see: http://php.net/manual/en/language.references.pass.php

Upvotes: 1

MH2K9
MH2K9

Reputation: 12039

Return the value from ifemptySet() & assign it to $site_name. Can try this

function  ifemptySet($who,$set){
    return $who ? $who : $set;
}

if(isset($_POST['saveinfosite'])){
    $site_name = strip_tags($_POST['site_name']);
    $site_name = ifemptySet($site_name, "null");
    echo $site_name;
}

Upvotes: 0

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