Reputation: 497
I have the following code, which works fine
#include <stdlib.h>
void transpose();
void main(){
transpose();
}
void transpose() {
int arr[] = {2, 3, 4, 1};
int l = sizeof (arr) / sizeof (arr[0]);
int i, j, k;
for (i = 0; i < l; i++) {
j = (i + 1) % l;
int copy[l];
for (k = 0; k < l; k++)
copy[k] = arr[k];
int t = copy[i];
copy[i] = copy[j];
copy[j] = t;
printf("{%d, %d, %d, %d}\n", copy[0], copy[1], copy[2], copy[3]);
}
}
However what I want to do is, pass an array to transpose function and the transpose function would return the list of arrays.
So I tried the following code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void print_array(int a[], int num_elements);
void main(){
int b[16];
int a[] = {2, 3, 4, 1};
c= transpose(a);
print_array(c,16);
}
int transpose(int arr) {
//int arr[] = {2, 3, 4, 1};
int b[16];
int l = sizeof (arr) / sizeof (arr[0]);
int i, j, k;
for (i = 0; i < l; i++) {
j = (i + 1) % l;
int copy[l];
for (k = 0; k < l; k++)
copy[k] = arr[k];
int t = copy[i];
copy[i] = copy[j];
copy[j] = t;
printf("{%d, %d, %d, %d}\n", copy[0], copy[1], copy[2], copy[3]);
b=copy;
}
return b;
}
void print_array(int a[], int num_elements)
{
int i;
for(i=0; i<num_elements; i++)
{
printf("%d ", a[i]);
}
printf("\n");
}
But some errors. I would like NOT to work with pointers, so how to tackle this?
Also I know the print_array function is defined to print single array, I will modify it to print all arrays by a for loop. Is that a correct approach?
Upvotes: 0
Views: 97
Reputation: 40145
Perhaps, rewrite as your desire. (Logic intact)
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void print_array(int **a, int num_elements);
int **transpose(int n, int arr[n]);
int main(){
int a[] = {2, 3, 4, 1};
int **c;
int n = sizeof(a)/sizeof(*a);
int i;
c= transpose(n, a);
print_array(c, n);
//deallocate
for(i=0;i<n;++i)
free(c[i]);
free(c);
return 0;
}
int **transpose(int n, int arr[n]){
int l = n;
int **b = malloc(l * sizeof(*b));//sizeof(*b) : sizeof(int *)
int i, j, k;
for (i = 0; i < l; i++) {
j = (i + 1) % l;
int *copy = malloc(l * sizeof(*copy));//sizeof(int)
for (k = 0; k < l; k++)
copy[k] = arr[k];
int t = copy[i];
copy[i] = copy[j];
copy[j] = t;
//printf("{%d, %d, %d, %d}\n", copy[0], copy[1], copy[2], copy[3]);
b[i] = copy;
}
return b;
}
void print_array(int **a, int num_elements){
int i, j;
for(i=0; i<num_elements; i++){
for(j=0; j<num_elements; j++)
printf("%d ", a[i][j]);
printf("\n");
}
}
Upvotes: 1