CODEWITHSUNDEEP
javascriptphpupload
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Reputation: 57196

PHP How can I get the file's name when it is too large?

How can I get the file's name when it is too large?

I can get its length using $_SERVER['CONTENT_LENGTH'] but what about its name?

// check that post_max_size has not been reached
// convert_to_bytes is the function turn `5M` to bytes because $_SERVER['CONTENT_LENGTH'] is in bytes.
if (isset($_SERVER['CONTENT_LENGTH']) 
    && (int) $_SERVER['CONTENT_LENGTH'] > convert_to_bytes(ini_get('post_max_size'))) 
{
  // ... with your logic
  throw new Exception('File too large!');
}

for instance, if I upload an mp3,

very-large.mp3 (size 11MB)

I would like to get its name which is very-large.mp3 is it possible? Or do I have to use javascript?

NOTE:

You will get

Array()

with $_FILES when the file is too large.

So then you can't get $_FILES[file]["name"]

Upvotes: 0

Views: 64

Answers (1)

Justinas
Justinas

Reputation: 43479

So if you have <input type="file" name="userFile"/> than you use it's name to get name from $_FILES global variable: echo "File {$_FILES['userFile']['name']} is too big.";

Upvotes: 1

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