CODEWITHSUNDEEP
pythonfactorization
Ellipticat
Ellipticat

Reputation: 198

Fermat Factorization not work (python)

I have written this code (in python) for factorize a integer in prime numbers (Fermat's theorem).

#!/usr/bin/python2

import random,math


n=590632926550117049 

a=math.ceil(math.sqrt(n))
b2=a*a-n

while math.sqrt(b2)!=math.floor(math.sqrt(b2)): 
    a=a+1
    b2=a*a-n

b=math.sqrt(b2)

p=a+b
q=a-b

print("p =",p)
print("q =",q)

The number n=590632926550117049 is the product of 57848543*10209987943 but my program returns: 1156469901*510720535. Why ?

EDIT: i.e. with 187 or 15 or another number works fine.

Upvotes: 1

Views: 762

Answers (1)

casevh
casevh

Reputation: 11424

math.sqrt() uses standard IEEE 64-bit values. It can only calculate accurately for arguments less than ~2**53. Your value for n is larger than that.

If you want exact integer square roots for large numbers, I would recommend gmpy2.

Disclaimer: I maintain gmpy2.

Edit: Here is an updated version of your program.

import gmpy2

n = 590632926550117049

a = gmpy2.isqrt(n) + 1
b2 = a * a - n

while not gmpy2.is_square(b2):
    a = a + 1
    b2 = a * a - n

b = gmpy2.isqrt(b2)

p = a + b
q = a - b

print("p =", p)
print("q =", q)

Upvotes: 2

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