CODEWITHSUNDEEP
javamongodbparsingbson
Masoud
Masoud

Reputation: 39

see the content of a .bson file using java

I have a very large .bson file.

Now I have two question:

  1. How can I see the content of that file? (I know it can do with "bsondump", but this command is slow, specialy for large database) (In fact I want to see the structure of that file)

  2. How can I see the content of that file using java?

Upvotes: 2

Views: 4734

Answers (1)

helmy
helmy

Reputation: 9497

You can easily read/parse a bson file in Java using a BSONDecoder instance such as BasicBSONDecoder or DefaultBSONDecoder. These classes are included in mongo-java-driver.

Here's a simple example of a Java implementation of bsondump.

import java.io.BufferedInputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;

import org.bson.BSONDecoder;
import org.bson.BSONObject;
import org.bson.BasicBSONDecoder;



public class BsonDump {

    public void bsonDump(String filename) throws FileNotFoundException {
        File file = new File(filename);
        InputStream inputStream = new BufferedInputStream(new FileInputStream(file));

        BSONDecoder decoder = new BasicBSONDecoder();
        int count = 0;
        try {
            while (inputStream.available() > 0) {

                BSONObject obj = decoder.readObject(inputStream);
                if(obj == null){
                    break;
                }
                System.out.println(obj);
                count++;

            }
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } finally {
            try {
                inputStream.close();
            } catch (IOException e) {
            }
        }
        System.err.println(String.format("%s objects read", count));
    }

    public static void main(String args[]) throws Exception {

        if (args.length < 1) {
            //TODO usage
            throw new IllegalArgumentException("Expected <bson filename> argument");
        }
        String filename = args[0];
        BsonDump bsonDump = new BsonDump();
        bsonDump.bsonDump(filename);

    }

}

Upvotes: 6

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