CODEWITHSUNDEEP
swiftstring-formatting
lostrva
lostrva

Reputation: 13

Properly formatting NSTimer in Swift

Would like to ask, how to properly format an NSTimer in the interval of 0.01? I would like to have something like 00:00.00 (mins, sec, msec)

When I run my code:

...

@IBAction func btn_play(sender: AnyObject) {
        timer = NSTimer.scheduledTimerWithTimeInterval(0.01, target: self, selector: Selector("result"), userInfo: nil, repeats: true)
    }

...

func result() {
    count++
    lbl_time.text = String(count)
}

...

I receive something like 1123 ( stands for 11 seconds 23 msecs) How would you transform it to eg:

00:11.23

I've tried some stuff with "substring" but with no sucess. I'm new to Swift, so I'm not aware what possibilities I have here. thx!

Upvotes: 0

Views: 609

Answers (1)

vacawama
vacawama

Reputation: 154573

Use integer division / and modulo % to calculate the values for minutes, seconds, and hundredths of a second, and then use the String convenience initializer which takes a format string to add the leading zeros and colons:

let count = 1234
let str = String(format:"%02d:%02d:%02d", (count/6000)%100, (count/100)%60, count%100)

This functionality comes from the Foundation framework. To use this convenience initializer for String, you must import Foundation (note: Foundation is imported by both import UIKit (iOS) and import Cocoa (OS X), so you usually don't import Foundation explicitly).

The NSString formatting methods follow the IEEE printf specification.

Upvotes: 1

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