Reputation: 104
I use xsl to reformat a list in sharepoint 2013 and I want to implement paging in the new list. So, first I want to know how to pass parameters from the url and read it from xsl.
https://stackoverflow.com/search.aspx?page=2
I want to get "page" value.
I use this code , but never work for me.
<xsl:param name="page"/>
and I read it like
<xsl:value-of select="$page" />
I almost finish my work and I want to just know how to read the URL variable .
Upvotes: 0
Views: 770
Reputation: 104
It work for me after I modify the original view xml from sharepoint physical folder under XSL (main.xsl).
I think it related to security problem, and when I create external xsl file and liked it with sharepoint list it will be not have the full trust !!
Upvotes: 0