CODEWITHSUNDEEP
iosjsonxcode
Pyae Phyoe Shein
Pyae Phyoe Shein

Reputation: 13787

NSJSONSerialization cannot load large json data from URL

NSURLRequest *request = [[NSURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://www.hrjournalmyanmar.com/test.cfm"]];

__block NSDictionary *json;
[NSURLConnection sendAsynchronousRequest:request
                                   queue:[NSOperationQueue mainQueue]
                       completionHandler:^(NSURLResponse *response, NSData *data, NSError *connectionError) {
                           json = [NSJSONSerialization JSONObjectWithData:data
                                                                  options:0
                                                                    error:nil];
                           NSLog(@"Async JSON: %@", json);

I cannot convince why I got (null) return message from above even json format and coding are correct. Above coding is correct when json data (field length) is small but field length is long and large, (null) error occurred.

Upvotes: 1

Views: 466

Answers (2)

Midhun MP
Midhun MP

Reputation: 107121

Your JSON is not valid. Please check it in JSONLint or JSON Editor

Issue is with the thumb key, the opening " is missing for that key.

In your JSON it's like:

thumb":"http: //mmjobs.mmdroid.biz/articles/articles234."

It should be like:

"thumb":"http: //mmjobs.mmdroid.biz/articles/articles234."

EDIT:

Based on your comments.

Still your JSON is not valid it contains a lot of new line characters and it makes it invalid. I solved your issue using the following method.

NSURLRequest *request = [[NSURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://www.hrjournalmyanmar.com/test.cfm"]];
__block NSDictionary *json;
[NSURLConnection sendAsynchronousRequest:request
                                   queue:[NSOperationQueue mainQueue]
                       completionHandler:^(NSURLResponse *response, NSData *data, NSError *connectionError)
{
    NSError *error = nil;
    NSString *jsonString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
    jsonString = [jsonString stringByReplacingOccurrencesOfString:@"\r\n" withString:@""];
    jsonString = [jsonString stringByReplacingOccurrencesOfString:@"\n" withString:@""];
    jsonString = [jsonString stringByReplacingOccurrencesOfString:@"\r" withString:@""];
    json = [NSJSONSerialization JSONObjectWithData:[jsonString dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingAllowFragments error:&error];


   if (!error)
   {
       NSLog(@"Async JSON: %@", json);
   }
   else
   {
       NSLog(@"Error: %@", error);
   }
}];

Note:

I won't recommend this approach, it's better to change the JSON at server side itself. Use the error argument, instead of passing nil to it. The error object will give you the exact error message.

Upvotes: 2

Moral
Moral

Reputation: 111

The issue is that you aren't creating a valid JSON format in your backend. If you try my snippet, works perfectly, but instead of creating my data in JSON is a NSString.

NSURLRequest *request = [[NSURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://www.hrjournalmyanmar.com/test.cfm"]];

[NSURLConnection sendAsynchronousRequest:request
                                   queue:[NSOperationQueue mainQueue]
                       completionHandler:^(NSURLResponse *response, NSData *data, NSError *connectionError) {

                           NSString* dataReceived = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];

                           NSLog(@"Async JSON: %@", dataReceived);
}];

Upvotes: 0

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