Reputation:
I am kinda stuck with a supposed to be simple code to check if the user has pressed "w" or "s".
Below you can see my code:
import pygame
pygame.init()
while True:
for event in pygame.event.get():
if event.type == pygame.KEYDOWN and event.key == pygame.K_w:
print('Forward')
elif event.type == pygame.KEYDOWN and event.key == pygame.K_s:
print('Backward')
Am I forgetting something here?
Thanks!
Upvotes: 2
Views: 28997
Reputation: 1
This might work:
from pygame import *
init()
if key.get_pressed()[K_w] == True:
print('Forwards')
if key.get_pressed()[K_s] == True:
print('Backwards')`
Upvotes: 0
Reputation:
import pygame
from pygame.locals import *
def main():
pygame.init()
pygame.display.set_caption("Move Box With Arrow Keys")
wndsize = (320, 240)
display = pygame.display.set_mode(wndsize)
x = 5
y = 5
black = (0, 0, 0)
white = (255, 255, 255)
rectpos = (x, y)
rectdim = (50, 50)
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_RIGHT:
x += 5
print("K_RIGHT")
if event.key == pygame.K_LEFT:
x -= 5
print("K_LEFT")
if event.key == pygame.K_UP:
y -= 5
print("K_UP")
if event.key == pygame.K_DOWN:
y += 5
print("K_DOWN")
# Don't allow coords below 0
if 0 > x:
x = 5
if 0 > y:
y = 5
# Don't allow overflow
if x + rectdim[0] > wndsize[0]:
x = wndsize[0] - rectdim[0] - 5
if y + rectdim[1] > wndsize[1]:
y = wndsize[1] - rectdim[1] - 5
rectpos = (x, y)
display.fill(white)
rect = pygame.draw.rect(display, black, ((rectpos), (rectdim)))
pygame.display.update()
main()
Upvotes: 0
Reputation: 21
it is no good to ask the gamer to keep hitting w to get the response. If you want to read the "pressed" state. You could consider the followings:
from pygame import *
import time
flag = False # The flag is essential.
DONE = False
screen = display.set_mode((500,500)) # 1180, 216
count=0
while not DONE:
event.pump() # process event queue
keys = key.get_pressed() # It gets the states of all keyboard keys.
#print("%d"%count,keys)
count+=1
if keys[ord('w')]: # And if the key is K_DOWN:
print("%d w down"%count)
if keys[ord('s')]: # And if the key is K_DOWN:
print("%d s down"%count)
time.sleep(0.1)
Upvotes: 1
Reputation: 261
This is what seems to me the most simple and understandable way to do it:
import pygame
pygame.init()
pygame.display.set_mode((300, 300))
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
pygame.quit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_w:
print('Forward')
elif event.key == pygame.K_s:
print('Backward')
Instead of using the sys.exit() method I prefer to just use pygame.quit()
Upvotes: 1
Reputation: 6251
A window needs to be created to receive key presses, the following works.
import pygame
import sys
pygame.init()
pygame.display.set_mode((100, 100))
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
sys.exit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_w:
print('Forward')
elif event.key == pygame.K_s:
print('Backward')
Upvotes: 3
Reputation:
Try this:
import pygame
pygame.init()
key = pygame.key.get_pressed()
while True:
for event in pygame.event.get():
if event.type == KEYDOWN and event.key == pygame.K_w:
print('Forward')
elif event.type == KEYDOWN and event.key == pygame.K_s:
print('Backward')
Upvotes: 0