Reputation: 855
I have requirement to create a parent and child property of JSON from same object which means it should be like
{"employee": {
"name":"skanda",
"id":"123",
"employee":[
{"id":"345"}
]
}
}
Here is my Java Object. Please let me know how can I do this. Should I create Inner classes and have instance of one more Employee object. Please advise. I have to design in such a way that the same should also be De-serialized on other end when passed through Rest WS. If I can use annotations please advise which annotations should be used in this case.
public class Employee {
private String name;
private String id;
private List<Employee> list = new ArrayList<Employee>();
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public List<Employee> getList() {
return list;
}
public void setList(List<Employee> list) {
this.list = list;
}
}
Upvotes: 1
Views: 2339
Reputation: 6217
You can use Jackson and annotations. You will need "jackson-databind".
On maven, add the dependency like this:
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.4.4</version>
</dependency>
With a POJO like this:
import java.util.List;
import com.fasterxml.jackson.annotation.JsonIdentityInfo;
import com.fasterxml.jackson.annotation.JsonRootName;
import com.fasterxml.jackson.annotation.ObjectIdGenerators;
@JsonRootName(value = "employee")
@JsonIdentityInfo(generator = ObjectIdGenerators.IntSequenceGenerator.class, property = "@id")
public class Employee {
private String name;
private String id;
private List<Employee> employee;
public String getName() {
return name;
}
public void setName(final String name) {
this.name = name;
}
public String getId() {
return id;
}
public void setId(final String id) {
this.id = id;
}
public List<Employee> getEmployee() {
return employee;
}
public void setEmployees(final List<Employee> employee) {
this.employee = employee;
}
}
And an example like this:
import java.util.ArrayList;
import java.util.List;
import org.junit.Assert;
import org.junit.Test;
import com.fasterxml.jackson.annotation.JsonInclude.Include;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationFeature;
public class EmployeeTest {
private static final String EXPECTED_JSON_RESULT = "{\"employee\":{\"@id\":1,\"name\":\"skanda\",\"id\":\"123\",\"employee\":[{\"@id\":2,\"id\":\"345\"}]}}";
@Test
public void serializationTest() throws JsonProcessingException {
final Employee emp1 = new Employee();
emp1.setId("123");
emp1.setName("skanda");
final Employee empL1 = new Employee();
empL1.setId("345");
final List<Employee> list = new ArrayList<>();
list.add(empL1);
emp1.setEmployees(list);
final ObjectMapper objectMapper = new ObjectMapper();
objectMapper.setSerializationInclusion(Include.NON_NULL);
objectMapper.configure(SerializationFeature.WRAP_ROOT_VALUE, true);
Assert.assertEquals(EXPECTED_JSON_RESULT, objectMapper.writeValueAsString(emp1));
}
}
Will generate a JSON like this:
{
"employee":{
"@id":1,
"name":"skanda",
"id":"123",
"employee":[
{
"@id":2,
"id":"345"
}
]
}
}
@JsonIdentityInfo
will help you on self-references, avoiding StackOverflowError
and is mapped for @id
property. You can remove, if you want.
For complete documentation, see https://github.com/FasterXML/jackson
Upvotes: 1
Reputation: 4925
You can achieve this using Jackson JSON library: http://jackson.codehaus.org/
One good tutorial which particularly addresses nested objects is here: http://www.mkyong.com/java/how-to-convert-java-object-to-from-json-jackson/
Apart from these, Google is your friend :)
Upvotes: 0