CODEWITHSUNDEEP
linuxbashshell
Selendi
Selendi

Reputation: 7

Bash script with argument that makes file executable

I need to make a bash script that checks if the file or directory exists,then if the file does,it checks the executable permission.I need to modify the script to be able to give a file executable permissions from an argument.

Example: Console input ./exist.sh +x file_name should make the file executable.

This is the unfinished code that checks if the file/directory exists and if the file is executable or not. I need to add the chmod argument part.

#!/bin/bash
file=$1
if [ -x $file ]; then
    echo "The file '$file' exists and it is exxecutable"

else
    echo "The file '$file' is not executable (or does not exist)"

fi

if [ -d $file ]; then
    echo "There is a directory named '$file'"

else
    echo "There is no directory named '$file'"

fi

Upvotes: 0

Views: 891

Answers (2)

Joe
Joe

Reputation: 28326

If you have optional arguments to your script, you need to check for them first.

In the case of just a couple of simple arguments, it would be simpler to check for them explicitly.

MAKEEXECUTABLE=0
while [ "${1:0:1}" = "+" ]; do
  case $1 in
     "+x")
         MAKEEXECUTABLE=1
        shift
        ;;
     *)
        echo "Unknown option '$1'"
        exit
   esac
done
file=$1

Then after you have determined that the file is not executable

if [ $MAKEEXECUTABLE -eq 1 ]; then
   chmod +x $file
fi

Should you decide to add more complex options, you may want to use something like getops:example of how to use getopts in bash

Upvotes: 1

SMA
SMA

Reputation: 37023

Add chmod something like:

if [ ! -x "$file" ]; then
   chmod +x $file
fi

This means if file does not have execute persmission, then add execute permission for the user.

Upvotes: 1

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