donde
donde

Reputation: 41

What is wrong with my ftp code?

I am using c# in .NEt 2.0 to simply try to upload a file. Everything seems ok in the code, but it keeps failing at when I go to create a stream from the FtpWebRequest.GetRequestStream method.

Here is the code...

        FtpWebRequest ftpRequest;
        FtpWebResponse ftpResponse;

        try
        {
            string fileName = Path.GetFileName(strCompleteFilePath);
            ftpRequest = (FtpWebRequest)FtpWebRequest.Create(new Uri("ftp://myhost/" + fileName));
            ftpRequest.Method = WebRequestMethods.Ftp.UploadFile;
            ftpRequest.Proxy = null;
            ftpRequest.UseBinary = true;
            ftpRequest.Credentials = new NetworkCredential("myUserID", "myPW");
            ftpRequest.KeepAlive = false;

            FileInfo ff = new FileInfo(strCompleteFilePath);
            byte[] fileContents = new byte[ff.Length];

            using (FileStream fr = ff.OpenRead()) 
            {
                fr.Read(fileContents, 0, Convert.ToInt32(ff.Length));
            }

            using (Stream writer = ftpRequest.GetRequestStream())
            {
                writer.Write(fileContents, 0, fileContents.Length);
            }

            ftpResponse = (FtpWebResponse)ftpRequest.GetResponse(); 
        }

And the error....

{System.Net.WebException: The remote server returned an error: (501) Syntax error in parameters or arguments.
   at System.Net.FtpWebRequest.SyncRequestCallback(Object obj)
   at System.Net.FtpWebRequest.RequestCallback(Object obj)
   at System.Net.CommandStream.InvokeRequestCallback(Object obj)
   at System.Net.CommandStream.Abort(Exception e)
   at System.Net.FtpWebRequest.FinishRequestStage(RequestStage stage)
   at System.Net.FtpWebRequest.GetRequestStream()

Upvotes: 4

Views: 7661

Answers (5)

Plastónico
Plastónico

Reputation: 25

Try

ftpRequest.UsePassive = false;

it works for me.

Upvotes: 1

Hans Passant
Hans Passant

Reputation: 941218

The FTP server is unhappy about the STOR command that .NET generates. Best place to look is in the log file for the server. Taking a wild guess: the path is unusual, you'd typical want to specify a directory name (like ftp://myhost/somedir/filename)

Upvotes: 1

JYelton
JYelton

Reputation: 36512

The line:

ftpRequest = (FtpWebRequest)FtpWebRequest.Create(new Uri("ftp://myhost" + fileName));

Might be a problem if your fileName variable doesn't include the necessary slashes.

Upvotes: 3

Mitchel Sellers
Mitchel Sellers

Reputation: 63126

You are missing a / in the path.

You are going to be creating a path that is ftp://myhostmyfile.txt if your file was called "myfile.txt", which I'm guessing should be ftp://myhost/myfile.txt

Therefore just add a / to the end of the ftp://myhost string.

Upvotes: 5

Hans Olsson
Hans Olsson

Reputation: 55001

This looks wrong:

ftpRequest = (FtpWebRequest)FtpWebRequest.Create(new Uri("ftp://myhost" + fileName));

Unless the contents of filename starts with a / I think you need to add one of those so it would be like:

ftpRequest = (FtpWebRequest)FtpWebRequest.Create(new Uri("ftp://myhost/" + fileName));

Upvotes: 4

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