CODEWITHSUNDEEP
pythonstring
Bobys
Bobys

Reputation: 677

Python remove first number from string if it's 0

I'm getting a string from a form format 07123456789 (it's a phone number) and I would like to remove the first number/character only if it's a zero. And after that add 44 in front. So the output will be 447123456789.

Which is the best way to do it?

Upvotes: 3

Views: 18378

Answers (5)

Hackaholic
Hackaholic

Reputation: 19733

str.lstrip is best for this case:

>>> s = '07123456789'
>>> '44'+s.lstrip('0')
'447123456789'
>>> s = '7123456789'
>>> '44'+s.lstrip('0')
'447123456789'

Upvotes: 3

Vivek Sable
Vivek Sable

Reputation: 10213

We can convert string into integer e.g.

>>> s = "07123456789"
>>> "44%s"%(int(s))
'447123456789'

We can use lstrip method of string which will remove all "0" from left of string. e.g.

>>> "44%s"%(s.lstrip("0"))
'447123456789'

If we want to consider only the first character from string then we can try following: (above two solution will not when more then one "0" at starting of string.)

>>> if s[0]=="0":
...   s = s[1:]
... 
>>> "44%s"%s
'447123456789'

Or go with solution from jamylak 

>>> s = '07123456789'
>>> "44%s%s"%(s[0].strip("0"), s[1:])
'447123456789'

Upvotes: 5

vaultah
vaultah

Reputation: 46523

Use str.startswith

In [11]: s = '07123456789'

In [12]: '44{}'.format(s[1:] if s.startswith('0') else s)
Out[12]: '447123456789'

Also, instead of formatting, you can join the strings together with + operator:

'44' + (s[1:] if s.startswith('0') else s)

If you're sure there's at most 1 zero at the beginning of the number, you can safely use str.lstrip or int conversion (see other answers).

Upvotes: 13

jamylak
jamylak

Reputation: 133504

Just another possible option:

>>> s = '07123456789'
>>> '44' + s[0].strip('0') + s[1:]
'447123456789'

Upvotes: 4

Mureinik
Mureinik

Reputation: 311053

One way to go about this is to cast to int to remove the zero at the beginning and then cast back to a str:

s = '07123456789'
s = '44'+str(int(s))

Upvotes: 1

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