CODEWITHSUNDEEP
pythonif-statement
Learner
Learner

Reputation: 51

Condition with pass statement

I'm trying to figure out how to check if line contains some substrings or not, if it does, print that string. If it doesn't, do nothing. For this do nothing thing, I found that there is a statement in Python that just holds space and does nothing, which is pass so I used it. but the result is all strings are being printed no matter the condition.

try:
  string = line.split(',')
  if string[0] != 'Aa' or string[0] != 'Bb':
    pass
  print string

Upvotes: 1

Views: 83

Answers (3)

user2555451
user2555451

Reputation:

That print string line is independent of the if-statement. Meaning, it will be executed regardless of whether or not your condition is true.

You would need an else: block to do what you want:

string = line.split(',')
if string[0] != 'Aa' and string[0] != 'Bb': # You need 'and' up here
  pass
else:
  print string # This will only be executed if the condition is false

But that is somewhat redundant. A better approach would be to just do:

string = line.split(',')
if string[0] == 'Aa' or string[0] == 'Bb':
  print string

or maybe:

string = line.split(',')
if string[0] in {'Aa', 'Bb'}:
  print string

Upvotes: 2

implicati0n
implicati0n

Reputation: 269

Just this:

string = line.split(',')
if string[0] == 'Aa' or string[0] == 'Bb':
    print string

You don't need pass

Upvotes: 4

Newb
Newb

Reputation: 2930

try/except is for error handling. I don't think you'll need it for this purpose.

string=line.split(',') is correct. It'll split the string into a list of strings according to commas.

The problem is print string. It's not inside the scope of the if statement, so the if statement has no effect on printing the string. You'll want something like this:

if string[0] != 'Aa' or string[0] != 'Bb':
    pass
else:
    print string

or better yet:

if string[0] == 'Aa' or string[0] == 'Bb':
    print string

Upvotes: 2

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