MT3
MT3

Reputation: 1061

How to use jQuery to show/hide divs based on radio button selection?

I have some radio buttons and I'd like to have different hidden divs show up based on which radio button is selected. Here's what the HTML looks like:

<form name="form1" id="my_form" method="post" action="">
    <div><label><input type="radio" name="group1" value="opt1">opt1</label></div>  
    <div><label><input type="radio" name="group1" value="opt2">opt2</label></div>  
    <div><label><input type="radio" name="group1" value="opt3">opt3</label></div>  
    <input type="submit" value="Submit">
</form>

....

<style type="text/css">
    .desc { display: none; }
</style>

....

<div id="opt1" class="desc">lorem ipsum dolor</div>
<div id="opt2" class="desc">consectetur adipisicing</div>
<div id="opt3" class="desc">sed do eiusmod tempor</div>

And here's my jQuery:

$(document).ready(function(){ 
    $("input[name$='group2']").click(function() {
        var test = $(this).val();
        $("#"+test).show();
    }); 
});

The reason I'm doing it that way is because my radio buttons and divs are being generated dynamically (the value of the radio button will always have a corresponding div). The code above works partially - the divs will show when the correct button is checked, but I need to add in some code to make the divs hide again once the button is unchecked. Thanks!

Upvotes: 39

Views: 136383

Answers (9)

thomas
thomas

Reputation: 915

You can use jQuery’s show() and hide() methods. Like below:

JQuery:

  $(document).ready(function(){
    $('input[type="radio"]').click(function(){
      var val = $(this).attr("value");
      var target = $("." + val);
      $(".msg").not(target).hide();
      $(target).show();
    });
  });

HTML:

<input type="radio" name="color" value="yellow"> Yellow
<input type="radio" name="color" value="red"> Red
<input type="radio" name="color" value="green"> Green

<div class="yellow msg">You have selected Yellow</div>
<div class="red msg">You have selected Red</div>
<div class="green msg">You have selected Green</div>

Here is an example: Show/hide DIV based on Radio Button click

Upvotes: 3

Siraj Ahmed
Siraj Ahmed

Reputation: 144

I wrote a simple code to unterstand you to how to make a show and hide radio buttons in jquery its very simple

<div id="myRadioGroup">

    Value Based<input type="radio" name="cars" checked="checked" value="2"  />

    Percent Based<input type="radio" name="cars" value="3" />
    <br>
    <div id="Cars2" class="desc" style="display: none;">
        <br>
        <label for="txtPassportNumber">Commission Value</label>
       <input type="text" id="txtPassportNumber" class="form-control" />
    </div>
    <div id="Cars3" class="desc" style="display: none;">
        <br>
        <label for="txtPassportNumber">Commission Percent</label>
       <input type="text" id="txtPassportNumber" class="form-control" />
    </div>
</div>
</div>

Jquery code

$(document).ready(function() {
    $("input[name$='cars']").click(function() {
        var test = $(this).val();

        $("div.desc").hide();
        $("#Cars" + test).show();
    });
});

give me comments

Upvotes: 0

Pradeep
Pradeep

Reputation: 21

Below code is perfectly workd for me:

$(document).ready(function(){
    $('input[type="radio"]').click(function(){
        var inputValue = $(this).attr("value");
        var targetBox = $("." + inputValue);
        $(".box").not(targetBox).hide();
        $(targetBox).show();
    });
});
.box{
        color: #fff;
        padding: 20px;
        display: none;
        margin-top: 20px;
    }
    .red{ background: #ff0000; }
    .green{ background: #228B22; }
    .blue{ background: #0000ff; }
    label{ margin-right: 15px; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div>
        <label><input type="radio" name="colorRadio" value="red"> red</label>
        <label><input type="radio" name="colorRadio" value="green"> green</label>
        <label><input type="radio" name="colorRadio" value="blue"> blue</label>
    </div>
    <div class="red box">You have selected <strong>red radio button</strong> so i am here</div>
    <div class="green box">You have selected <strong>green radio button</strong> so i am here</div>
    <div class="blue box">You have selected <strong>blue radio button</strong> so i am here</div>

Upvotes: 1

Z. Zlatev
Z. Zlatev

Reputation: 4820

Update 2015/06

As jQuery has evolved since the question was posted, the recommended approach now is using $.on

$(document).ready(function() {
    $("input[name=group2]").on( "change", function() {

         var test = $(this).val();
         $(".desc").hide();
         $("#"+test).show();
    } );
});

or outside $.ready()

$(document).on( "change", "input[name=group2]", function() { ... } );

Original answer

You should use .change() event handler:

$(document).ready(function(){ 
    $("input[name=group2]").change(function() {
        var test = $(this).val();
        $(".desc").hide();
        $("#"+test).show();
    }); 
});

should work

Upvotes: 50

Dr. Hans-Peter St&#246;rr
Dr. Hans-Peter St&#246;rr

Reputation: 26006

An interesting solution is to make this declarative: you just give every div that should be shown an attribute automaticallyVisibleIfIdChecked with the id of the checkbox or radio button on which it depends. That is, your form looks like this:

<form name="form1" id="my_form" method="post" action="">
    <div><label><input type="radio" name="group1" id="rdio1" value="opt1">opt1</label></div>  
    <div><label><input type="radio" name="group1" id="rdio2" value="opt2">opt2</label></div>  
</form>
....
<div id="opt1" automaticallyVisibleIfIdChecked="rdio1">lorem ipsum dolor</div>
<div id="opt2" automaticallyVisibleIfIdChecked="rdio2">consectetur adipisicing</div>

and have some page independent JavaScript that nicely uses functional programming:

function executeAutomaticVisibility(name) {
    $("[name="+name+"]:checked").each(function() {
        $("[automaticallyVisibleIfIdChecked=" + this.id+"]").show();
    });
    $("[name="+name+"]:not(:checked)").each(function() {
        $("[automaticallyVisibleIfIdChecked=" + this.id+"]").hide();
    });
}

$(document).ready( function() {
    triggers = $("[automaticallyVisibleIfIdChecked]")
        .map(function(){ return $("#" + $(this).attr("automaticallyVisibleIfIdChecked")).get() })
    $.unique(triggers);
    triggers.each( function() {
        executeAutomaticVisibility(this.name);
        $(this).change( function(){ executeAutomaticVisibility(this.name); } );
    });
});

Similarily you could automatically enable / disable form fields with an attribute automaticallyEnabledIfChecked.

I think this method is nice since it avoids having to create specific JavaScript for your page - you just insert some attributes that say what should be done.

Upvotes: 5

Rajesh Hatwar
Rajesh Hatwar

Reputation: 1933

<script type="text/javascript">
$(function() {
    $("[name=toggler]").click(function(){
            $('.toHide').hide();
            $("#blk-"+$(this).val()).show('slow');
    });
 });
</script>
</head>
<body>
<label><input id="rdb1" type="radio" name="toggler" value="1" />Book</label>
<label><input id="rdb2" type="radio" name="toggler" value="2" />Non-Book</label>

<div id="blk-1" class="toHide" style="display:none">

    <form action="success1.html">

        Name1:<input type="text" name="name">
             <input type="submit" name="submit">

    </form>

</div>
<div id="blk-2" class="toHide" style="display:none">

    <form action="success1.html">

        Name2:<input type="text" name="name">
             <input type="submit" name="submit">

    </form>
</div>

Upvotes: 5

Ste Yeu
Ste Yeu

Reputation: 157

$(document).ready(function(){ 
    $("input[name=group1]").change(function() {
        var test = $(this).val();
        $(".desc").hide();
        $("#"+test).show();
    }); 
});

It's correct input[name=group1] in this example. However, thanks for the code!

Upvotes: 7

Bharat
Bharat

Reputation: 726

The simple jquery source for the same -

$("input:radio[name='group1']").click(function() {      
    $('.desc').hide();
    $('#' + $("input:radio[name='group1']:checked").val()).show();
});

In order to make it little more appropriate just add checked to first option --

<div><label><input type="radio" name="group1" value="opt1" checked>opt1</label></div>  

remove .desc class from styling and modify divs like --

<div id="opt1" class="desc">lorem ipsum dolor</div>
<div id="opt2" class="desc" style="display: none;">consectetur adipisicing</div>
<div id="opt3" class="desc" style="display: none;">sed do eiusmod tempor</div>

it will really look good any-ways.

Upvotes: 4

albertein
albertein

Reputation: 27150

Just hide them before showing them:

$(document).ready(function(){ 
    $("input[name$='group2']").click(function() {
        var test = $(this).val();
        $("div.desc").hide();
        $("#"+test).show();
    }); 
});

Upvotes: 39

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