Reputation: 32459
I have the following class:
class BaseCache<T: Equatable>: NSObject {
var allEntities = [T]()
// MARK: - Append
func appendEntities(newEntities: [T]) {
....
}
}
Now I want to subclass it, but I get annoying error, that my type "does not conform to protocol 'Equatable'":
It seems generics in Swift are real pain-in-the-ass.
Upvotes: 17
Views: 24175
Reputation: 159
this should work: < swift 4 >
class TrackingCache<T: AftershipTracking>: BaseCache<T>
Another example:
protocol P {
}
class C: P {
}
class CS: C {
}
class L<T:P> {
let c: T
init(_ c: T) {
self.c = c
}
}
class LS<T:CS>:L<T> {
}
let i = LS(CS())
i.c
c
is CS
now.
Upvotes: 9
Reputation: 6494
Your class definition of TrackingCache
is wrong. It repeats the generic parameter:
class TrackingCache<AftershipTracking>: BaseCache<AftershipTracking> { }
It should be left out:
class TrackingCache: BaseCache<AftershipTracking> { }
This triggers the underlying swift error Classes derived from generic classes must also be generic
. You can work around this issue by specifying a type parameter that is required to be or inherit from AftershipTracking:
class TrackingCache<T: AftershipTracking>: BaseCache<AftershipTracking> { }
Full example:
class BaseCache<T: Equatable>: NSObject {
var items: [T] = []
func appendItems( items: [T]) {
self.items += items
didAppendItems()
}
func didAppendItems() {} // for overriding
}
class AftershipTracking: NSObject {
var identifier: Int
init( identifier: Int) {
self.identifier = identifier
super.init()
}
}
extension AftershipTracking: Equatable { }
func ==( lhs: AftershipTracking, rhs: AftershipTracking) -> Bool {
return lhs.identifier == rhs.identifier
}
class TrackingCache<T: AftershipTracking>: BaseCache<AftershipTracking> {
override func didAppendItems() {
// do something
}
}
let a = TrackingCache<AftershipTracking>()
let b = TrackingCache<AftershipTracking>()
a.appendItems( [AftershipTracking( identifier: 1)])
b.appendItems( [AftershipTracking( identifier: 1)])
let result = a.items == b.items // true
Upvotes: 24